Let h = height of the box,
x = side length of the base.
Volume of the box is

.
So

Surface area of a box is S = 2(Width • Length + Length • Height + Height • Width).
So surface area of the box is


The surface are is supposed to be the minimum. So we'll need to find the first derivative of the surface area function and set it to zero.

![4x = \frac{460}{ x^{2} } \\ 4x^{3} = 460 \\ x^{3} = 115 \\ x = \sqrt[3]{115} = 4.86](https://tex.z-dn.net/?f=%204x%20%3D%20%5Cfrac%7B460%7D%7B%20x%5E%7B2%7D%20%7D%20%20%5C%5C%20%204x%5E%7B3%7D%20%3D%20460%20%20%5C%5C%20x%5E%7B3%7D%20%3D%20115%20%20%5C%5C%20x%20%3D%20%20%5Csqrt%5B3%5D%7B115%7D%20%3D%204.86%20)
Then

So the box is 4.86 in. wide and 4.87 in. high.
Answer:
Happy Birthday to you too.
Using the intersecting secants theorem, QS*QR=QP*QM
3*13=2*(x+2)
39=2x+4
2x=35
x=17.5
Answer:
Point B
Step-by-step explanation:
5 milk choc and 8 dark choc....total of 13 chocolates
P(1st pick is milk choc) = 5/13
do not replace
P(2nd pick is milk choc) = 4/12 which reduces to 1/3
P(both picks are milk choc) = 5/13 * 1/3 = 5/39 <== or 12.8%