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3 years ago

Solve for the indicated variable. 8x + 4y = 12; y

Mathematics

1 answer:

Ket [755]3 years ago

4 0

Answer:

$y=-2x+3$

Step-by-step explanation:

Given: $8x+4y=12$

To solve for y, let us first isolate y on one side of the equation. We can do this by subtracting $8x$ from the left and move it to the right. We then get:

$4y=12-8x$

Now, we have y isolated. We now have to remove the 4 from the y. The only way to do this is divide both sides by 4. We then get our final answer:

$y=3-2x$

We can clean this up by putting it in a common form, slope-intercept form:

$y=-2x+3$

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The half of the day from midday to midnight can be described as

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24hours divided by 2 is 12

Step-by-step explanation:

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4 years ago

Write -2 + 4 + -8 + ...+ 64 +-128 in sigma notation. Then determine the sum.

Grace [21]

It would be -70. Your welcome

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3 years ago

can someone please help how did i get this wrong . the question says wich of the following could be used to estimate quotient 34

schepotkina [342]

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Step-by-step explanation:

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2 years ago

By what percent change if the numerator is decreased by 10% and the denominator is decreased by 70%

hjlf

Answer:

It increases x3.

Step-by-step explanation:

Let's say the fraction to begin with was 100/100. Ignore the fact that it isn't fully reduced and it is an improper fraction.

10% of 100 is 10, so the numerator is now 90 (decrease=get smaller; 100-10=90).

70% of 100 is 70, so the denominator is now 30 (decrease=get smaller; 100-70=30).

Our fraction is now 90/30 which, when fully reduced, equals 3.00. Since 100/100 equals 1.00, it has increased by 2.00 (3x bigger).

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3 years ago

Two airplanes are flying in the air at the same height. Airplane A is flying east at 300mi/h and airplane B is flying north at 2

Ipatiy [6.2K]

Answer:

$\frac{dAB}{dt}=340 mil/h$

Step-by-step explanation:

The change of distance over time of the plain A is 300 mi/hour and 200 mi/hour for plane B. O is the point of the airport.

So, the distance from A to O AO = 90 miles and BO = 120 miles.

Now, we have a right triangle here. We can use the Pythagorean theorem, so the distance between the planes will be:

$AB^{2} =AO^{2}+BO^{2}$ (1)

$AB =\sqrt{AO^{2}+BO^{2}}=$

$AB =\sqrt{90^{2}+120^{2}}=150 miles$

If we take the derivative of the equation (1) we could find the change of the distance between planes.

$2AB\frac{dAB}{dt}=2AO\frac{dAO}{dt}+2BO\frac{dBO}{dt}$

$2*150\frac{dAB}{dt}=2*90*300+2*120*200=102000 mil/h$

$\frac{dAB}{dt}=\frac{102000}{150*2}$

Finally,

$\frac{dAB}{dt}=340 mil/h$

I hope it helps you!

6 0

3 years ago

Solve for the indicated variable. 8x + 4y = 12; y​

Solve for the indicated variable. 8x + 4y = 12; y