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lesya [120]
3 years ago
5

Find the volume of a cone that has radius = 2 1/2 and height = 5.

Mathematics
2 answers:
Andreas93 [3]3 years ago
7 0

Answer:

98.1 is your anwser I know this kinds of stuff

muminat3 years ago
6 0

Step-by-step explanation:

v=22/7×r^2×h/3

=22/7×21/2×5/3

=33/5

=11cm^3

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katrin2010 [14]

9514 1404 393

Answer:

  A, D, E . . . not a function

  B, C . . . a function

Step-by-step explanation:

Look at the lists of first numbers:

  {2, 3, 5, 2} . . . 2 is repeated, not a function

 {3, -3, 0, 5} . . . no repeats, is a function

  {1, 2, 3, 4} . . . no repeats, is a function

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7 0
3 years ago
Which point is located at (4, 1) <br><br><br><br><br> A<br> B<br> C<br> D
marissa [1.9K]

Answer:

A

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
Can someone please help me with this geometry question?
Masteriza [31]

Answer:

25

Step-by-step explanation:

7 0
4 years ago
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Find the equation, f(x) = a(x-h)2 + k, for a parabola that passes through the point (1,-7) and has (2,- 4) as its vertex. What i
MAVERICK [17]
(h;\ k)\ -\ \text{the coordinates of the vertex}

\text{therefore we have}\ f(x)=a(x-2)^2-4
 
<span>\text{a parabola that passes through the point (1,-7)}

</span><span>\text{substitute the coordinates of the point (1;-7) to the equation:}

(1;-7)\to x=1;\ y=-7\\\\-7=a(1-2)^2-4\\\\-7=a(-1)^2-4\\\\-7=a-4\ \ \ |+4\\\\a=-3

</span><span>
</span>Answer:\ \text{c.The vertex form of the equation is}\ f(x)=-3(x-2)^2-4.\\\text{The standard form of the equation is}\ f(x)=-3x^2+12x-16
4 0
4 years ago
Solve the equation in the complex number system.
tatiyna
To get rid of x^{3}, you have to take the third root of both sides:
\sqrt[3]{x^{3}} = \sqrt[3]{1}
But that won't help you with understanding the problem. It is better to write x^{3}-1 as a product of 2 polynomials:
x^{3}-1 = (x-1)\cdot (x^{2} +x +1)
From this we know, that x-1 = 0 => x = 1 is the solution. Another solutions (complex roots) are the roots of quadratic equation.
3 0
3 years ago
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