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3 years ago

A point where two or more lines connect

Mathematics

1 answer:

Thepotemich [5.8K]3 years ago

6 0

Answer:

The vertex

Step-by-step explanation:

The vertex is the point that the lines connect

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PLEASE HELP! The table shows the number of championships won by the baseball and softball leagues of three youth baseball divisi

Irina18 [472]

Answer:

Question 1: $P ( B | Y ) = \frac{ P ( B and Y)}{ P (Y)} = \frac{ \frac{2}{16}}{ \frac{4}{16}} = \frac{1}{2}$

Question 2:

A. $P ( Y | B ) = \frac{ P(Y and B) }{ P(B) } = \frac{ \frac{2}{16} }{ \frac{6}{16} } = \frac{1}{3}$

B. $P( Z | B ) = \frac{ P ( Z and B)}{ P (B)}= \frac{ \frac{1}{16} }{ \frac{6}{16} } = \frac{1}{6}$

C. $P((Y or Z)|B) = \frac{ P ((Y or Z) and B)}{P(B)}= \frac{ \frac{3}{16}}{ \frac{6}{16}}= \frac{1}{2}$

Step-by-step explanation:

Conditional probability is defined by

$P(A|B)= \frac{P(A and B)}{P(B)}$

with P(A and B) beeing the probability of both events occurring simultaneously.

Question 1:

B: Baseball League Championships won, beeing

$P ( B ) = \frac{ 6 }{16}$

Y: Championships won by the 10 - 12 years old, beeing

$P ( Y)= \frac{ 4 }{ 16 }$

then

P( B and Y)= \frac{ 2 }{ 16 }[/tex]

By definition,

$P ( B | Y ) = \frac{ P ( B and Y)}{ P (Y)} = \frac{ \frac{2}{16} }{ \frac{4}{16} } = \frac{1}{2}$

Question 2.A:

Y: Championships won by the 10 - 12 years old, beeing

$P ( Y)= \frac{ 4 }{ 16 }$

B: Baseball League Championships won, beeing

$P ( B ) = \frac{ 6 }{16}$

then

P( B and Y)= \frac{ 2 }{ 16 }[/tex]

By definition,

$P ( Y | B ) = \frac{ P(Y and B) }{ P(B) } = \frac{ \frac{2}{16} }{ \frac{6}{16} } = \frac{1}{3}$

Question 2.B:

Z: Championships won by the 13 - 15 years old, beeing

$P ( Z)= \frac{ 1 }{ 16 }$

B: Baseball League Championships won, beeing

$P ( B ) = \frac{ 6 }{16}$

then

P( Z and B)= \frac{ 1 }{ 16 }[/tex]

By definition,

$P( Z | B ) = \frac{ P ( Z and B)}{ P (B)}= \frac{ \frac{1}{16} }{ \frac{6}{16} } = \frac{1}{6}$

Question 3.B

Y: Championships won by the 10 - 12 years old, beeing

$P ( Y)= \frac{ 4 }{ 16 }$

Z: Championships won by the 13 - 15 years old, beeing

$P ( Z)= \frac{ 1 }{ 16 }$

then

$P (Y or Z) = P(Y) + P(Z) = \frac{6}{16}$

B: Baseball League Championships won, beeing

$P ( B ) = \frac{ 6 }{16}$

$P((YorZ) and B)= \frac{3}{16}$

By definition,

$P((Y or Z)|B) = \frac{ P ((Y or Z) and B)}{P(B)}= \frac{ \frac{3}{16}}{ \frac{6}{16}}= \frac{1}{2}$

3 0

3 years ago

Can somebody please help me with this

BartSMP [9]

You just need pythagorean theorem c=a2+b2=72+42≈8.06226

7 0

3 years ago

A building manager installs sensors to see how often people turn off the lights when they leave the room. After a month the mana

vichka [17]

Answer:

D. 68%

Step-by-step explanation:

The following statistics are given;

sample mean = 47%

s = 5% ; the sample standard deviation

n = 625 ; the sample size

The confidence interval for a population mean is given as;

sample mean ± z-score* $\frac{s}{\sqrt{n} }$

Substituting the above values we have;

47 ± z-score* $\frac{5}{\sqrt{625} }$

47 ± z-score*0.2

The confidence interval has been given as;

lower limit = 46.8%

upper limit = 47.2%

We can use any of these two values with the above expression to solve for the z-score. Using the lower limit we have the following equation;

47 - z-score*0.2 = 46.8

-z-score*0.2 = 46.8 - 47

-z-score*0.2 = -0.2

z-score = 1

The area of the standard normal curve between -1 and +1 will be the confidence level for the given confidence interval.

Pr( -1<Z<1 ) = 0.68 = 68%

From the Empirical rule

6 0

4 years ago

Read 2 more answers

Please answer this correctly

V125BC [204]

Answer:

1/6

Step-by-step explanation:

P(8) = number of 8's / total = 1/3

Then keeping the card so we have 7 and 9

P(7) = number of 7's / total = 1/2

P(8, keep, 7) = 1/3 * 1/2 = 1/6

4 0

4 years ago

Select the correct answer.

mash [69]

Answer:

The answer is B because it's all real numbers since it won't stop

Step-by-step explanation:

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3 years ago