Find mean, median and mode of 140, 130, 90, 80, 60, 50, 30, 20, 10, 0
Alecsey [184]
For the mean you would have to add up all the numbers up and divide by the amount of numbers. For your problem you would get 610/10= 61.
For the median you would arrange all the numbers in order from least to greatest and cancel one from the left and one from the right each time. Since there is no middle number, the closest would be 50 and 60. Thus you you add 50+60 and get 110 and then divide by 2 giving you 55.
For the mode, there is no mode because none of the numbers repeat more than once.
I hope this clarifies your doubt. :)
Answer:
I'm pretty sure it's +(-6).
Step-by-step explanation:
Basically for these, you find the slope. The slope equation is y1-y2/x1-x2.
Pick two points.
I'll just do (1,15) and (2,9).
15-9/1-2 = 6/-1 = -6.
I don't know if you were taught it this way, but my math teacher always told us that the rate of change had to be positive.
So you'd say the rate of change is +(-6), not -6.
Hope that sorta helped lol
2.5h - 15 = 4h. -15 = 1.5h. -10 = h. Your answer is h = -10
just like the previous one, we sum the sides to get the perimeter.
<span>The number of x-intercepts that appear on the graph of the function
</span>f(x)=(x-6)^2(x+2)^2 is two (2): x=6 (multiplicity 2) and x=-2 (multiplicity 2)
Solution
x-intercepts:
f(x)=0→(x-6)^2 (x+2)^2 =0
Using that: If a . b =0→a=0 or b=0; with a=(x-6)^2 and b=(x+2)^2
(x-6)^2=0
Solving for x. Square root both sides of the equation:
sqrt[ (x-6)^2] = sqrt(0)→x-6=0
Adding 6 both sides of the equation:
x-6+6=0+6→x=6 Multiplicity 2
(x+2)^2=0
Solving for x. Square root both sides of the equation:
sqrt[ (x+2)^2] = sqrt(0)→x+2=0
Subtracting 2 both sides of the equation:
x+2-2=0-2→x=-2 Multiplicity 2
