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irga5000 [103]
2 years ago
8

Please solve this equations y=6x²-5,y=17x-6/x​

Mathematics
1 answer:
Amiraneli [1.4K]2 years ago
5 0

Answer:

x=3, y = 49\\x=0.5, y = -3.5\\x=-0.67, y = -2.31

Step-by-step explanation:

y=6x^2-5\\y=17x-\frac{6}{x}

Let's substitute the first equation into the second one.

6x^2-5=17x-\frac{6}{x}

6x^3-17x^2-5x+6=0 - Multiply by x and bring all the terms to one side.

I'll use my graphical calculator to solve this but you could factor:

x=3\\x=0.5\\x=-0.67 (All rounded to 2 decimal places)

Now we can substitute these x values into an equation for y.

y=6x^2 - 5

x=3, y = 49\\x=0.5, y = -3.5\\x=-0.67, y = -2.31

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3 years ago
A bakery sold 208 pounds of bread last week. This is about 5 times as many pounds as were sold this week. About how many pounds
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Answer:

41.6 pounds

Step-by-step explanation:

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4 0
3 years ago
Read 2 more answers
"A seed randomly blows around a complex habitat. It may land on any of three different soil types: a high-quality soil that give
mestny [16]

Answer:

a. answer to a can be found in the attached file

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0.24+0.06+0.05 = 0.35

c. Assume that the seed has a 0.2 chance of dying before it lands in a habitat. What is its  overall probability of survival?

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Step-by-step explanation:

"A seed randomly blows around a complex habitat. It may land on any of three different soil types: a high-quality soil that gives a 0.8 chance of seed survival, a medium-quality soil that gives a 0.3 chance of survival, and a low-quality soil that gives only a 0.1 chance of survival. These three soil types (high, medium, and low) are present in the habitat in proportions of 30:20:50, respectively. The probability that a seed lands on a particular soil type is proportional to the frequency of that type in the habitat. a. Draw a probability tree to determine the probabilities of survival under all possible circumstances. b. What is the probability of survival of the seed, assuming that it lands"c. Assume that the seed has a 0.2 chance of dying before it lands in a habitat. What is its overall probability of survival?

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b. Pr[survival] = Pr[good&survive]+Pr[medium&survive]+Pr[low&survive]=

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c. Assume that the seed has a 0.2 chance of dying before it lands in a habitat. What is its  overall probability of survival?

Pr[survival] = Pr[survival|lands] * Pr[lands] = 0.35 * 0.2 = 0.07

Download docx
7 0
3 years ago
What other way can I represent 2 1/3 ?
sveta [45]
The following is also equivalent to 2 1/3:

2.33
7/3

Hope this helps, let me know if you have any other questions.


3 0
3 years ago
Read 2 more answers
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iVinArrow [24]

Answer:

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Step-by-step explanation:

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