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UkoKoshka [18]
3 years ago
11

How to find the distance between two lines in 3d?

Mathematics
1 answer:
Nastasia [14]3 years ago
7 0
Use graph paper, draw the 3d shape and count the squares as one unit each

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Find the sum of the equation
stealth61 [152]

Answer:

\frac{{y}^{2}+13y-6}{{(y-1)}^{2}(y+7)}

Step-by-step explanation:

1)  Rewrite {y}^{2}-2y+1y  in the form{a}^{2}-2ab+{b}^{2}, where a = y and b = 1.

\frac{y}{{y}^{2}-2(y)(1)+{1}^{2}}+\frac{6}{{y}^{2}+6y-7}

2)  Use Square of Difference: {(a-b)}^{2}={a}^{2}-2ab+{b}^{2}.

\frac{y}{{(y-1)}^{2}}+\frac{6}{{y}^{2}+6y-7}

3)  Factor {y}^{2}+6y-7.

1 - Ask: Which two numbers add up to 6 and multiply to -7?

-1 and 7

2 - Rewrite the expression using the above.

(y-1)(y-7)

Outcome/Result: \frac{y}{(y-1)^2} +\frac{6}{(y-1)(y+7)}

4) Rewrite the expression with a common denominator.

\frac{y(y+7)+6(y-1)}{{(y-1)}^{2}(y+7)}

5)  Expand.

\frac{{y}^{2}+7y+6y-6}{{(y-1)}^{2}(y+7)}

6) Collect like terms.

\frac{{y}^{2}+(7y+6y)-6}{{(y-1)}^{2}(y+7)}

7) Simplify  {y}^{2}+(7y+6y)-6y  to  {y}^{2}+13y-6y

\frac{{y}^{2}+13y-6}{{(y-1)}^{2}(y+7)}

5 0
2 years ago
Read 2 more answers
A square has an area of 9 cm². Find its perimeter
dlinn [17]

Answer:

12

Step-by-step explanation:

area is base x height. 3×3 is 9. all sides of a square are equal so 3+3+3+3= the perimeter which is 12.

8 0
2 years ago
Read 2 more answers
A triangle has two sides of length 9 and 14 what is the smallest possible whole number length for the third side
melisa1 [442]

Let the third side = x.

The sum of any two sides must be greater than the third side

14 + 9 > x

  23 > x

14 + x > 9

   x > -5

9 + x > 14

   x > 5

So 5 < x < 23

6 0
2 years ago
What is the simplified form of cos​ C ?<br><br> A. √2/2<br> B. 1<br> C. √2<br> D. √5/2
Kruka [31]
The answer is D !!!!!
8 0
3 years ago
Read 2 more answers
Noah manages a buffet at a local restaurant. He charges $10 for the buffet. On average, 16 customers choose the buffet as their
kicyunya [14]

Answer:

$3 max

Step-by-step explanation:

Charge= b, Customer= c, Revenue= r

r= bc, currently, r= 16*10= $160

We know that: b+1 ⇒ c-2  and the target is r ≥ 130

So, this will all be reflected as:

b=10+x ⇒ c= 16-2x

  • (10+x)(16-2x) ≥ 130
  • 160 -20x +16x - 2x² ≥ 130
  • -2x² - 4x + 30 ≥ 0
  • x² + 2x -15 ≤ 0
  • (x+1)² ≤ 4²
  • x+1 ≤ 4 (negative value not considered)
  • x ≤ 3

As we see the max increase amount is $3, when the revenue will be:

(10+3)*(16-3*2)= 13*10= $130

8 0
3 years ago
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