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Zanzabum
2 years ago
10

Please help me on this

Mathematics
2 answers:
Nastasia [14]2 years ago
5 0

Answer:

Points H, J, G, and K

Step-by-step explanation:

For quadrats the right top is 1

left top is 2

left bottom is 3

right bottom is 4

and it is asking for the forth one so look at the right bottom "square"

G and K are on the line but that still makes them part of a Quadratic Just they get to be part of 2 of them like...

G is 3 and 4

K is 1 and 4

Leviafan [203]2 years ago
4 0
Puppy...have a puppy.

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Complete the two-column proof.
algol13

Answer:

a

Step-by-step explanation:

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3 years ago
A circular swimming pool has a radius of 28ft. There is a path all the way around the pool that's 4ft wide. A fence is going to
Natalka [10]

Answer:

Therefore 200.96 ft.of fencing are needed to go around the pool path.

Step-by-step explanation:

Given, a circular swimming pool has a radius of 28ft. There is a path all the way around the pool. The width of the path 4 ft.

The radius of the outside edge the pool path is

= Radius of the pool + The width of the path

= (28+4) ft

= 32 ft.

To find the length of fencing, we need to find the circumference of outside the pool path.

Here r= 32 ft

The circumference of outside edge of the pool path

=2\pi r

=(2\times 3.14 \times 32) ft

=200.96 ft.

Therefore 200.96 ft.of fencing are needed to go around the pool path.

3 0
3 years ago
what does "relationship" mean in the question, "what is the relationship between 4's in the number 4,400?
FromTheMoon [43]
Its the connection between those numbers
3 0
3 years ago
A square pyramid has side lengths each measuring 8 centimeters. The height of the pyramid is 3 centimeters,
tino4ka555 [31]
You answer would be 80 cm^2
7 0
3 years ago
A bucket that weighs 6 lb and a rope of negligible weight are used to draw water from a well that is 80 ft deep. The bucket is f
zaharov [31]

Answer:

3200 ft-lb

Step-by-step explanation:

To answer this question, we need to find the force applied by the rope on the bucket at time t

At t=0, the weight of the bucket is 6+36=42 \mathrm{lb}

After t seconds, the weight of the bucket is 42-0.15 t \mathrm{lb}

Since the acceleration of the bucket is the force on the bucket by the rope is equal to the weight of the bucket.

If the upward direction is positive, the displacement after t seconds is x=1.5 t

Since the well is 80 ft deep, the time to pull out the bucket is \frac{80}{2}=40 \mathrm{~s}

We are now ready to calculate the work done by the rope on the bucket.

Since the displacement and the force are in the same direction, we can write

W=\int_{t=0}^{t=36} F d x

Use x=1.5 t and F=42-0.15 t

W=\int_{0}^{36}(42-0.15 t)(1.5 d t)

=\int_{0}^{36} 63-0.225 t d t

=63 \cdot 36-0.2 \cdot 36^{2}-0=3200 \mathrm{ft} \cdot \mathrm{lb}

=\left[63 t-0.2 t^{2}\right]_{0}^{36}

W=3200 \mathrm{ft} \cdot \mathrm{lb}

4 0
3 years ago
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