Answer:
2^11
Explanation:
Physical Memory Size = 32 KB = 32 x 2^10 B
Virtual Address space = 216 B
Page size is always equal to frame size.
Page size = 16 B. Therefore, Frame size = 16 B
If there is a restriction, the number of bits is calculated like this:
number of page entries = 2^[log2(physical memory size) - log2(n bit machine)]
where
physical memory size = 32KB which is the restriction
n bit machine = frame size = 16
Hence, we have page entries = 2^[log2(32*2^10) - log2(16)] = 2ˆ[15 - 4 ] = 2ˆ11
Answer:
- Information services and support
- Programming and software development
- Network systems administration
Explanation:
The company has finished designing a software program, but users aren’t sure how to use it. <u>interactive media</u>
Several people in the human resources department need new software installed. <u>information services and support</u>
An employee has an idea for a software program that can save the company time, but doesn’t know how to write it. <u> programming and software development</u>
A new branch of the company is opening soon, and the computers there need to be connected to the Internet. <u>network systems administration</u>
<u>OAmalOHopeO</u>
