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2 years ago

f(x)=x2+5x-4 has a domain D={-4,-2,0,3,5} find the range (f(x)) value for each x value in the domain

Mathematics

1 answer:

True [87]2 years ago

5 0

Answer:

The range here is the set {8, -10, -4, 20, 32}.

Step-by-step explanation:

Please use " ^ " to denote exponentiation. Thanks. f(x)=x^2 + 5x - 4

f(-4)=(-4)^2 + 5(-4) - 4 = 8

f(-2)=(-2)^2 + 5(-1) - 4 = -10

f(0)=0^2 + 5(0) - 4 = -4

f(3) =3^2 + 5(3) - 4 = 20

f(4)=4^2 + 5(4) - 4 = 32

In this problem we have to calculate the actual function values for the given domain (input values). The range here is the set {8, -10, -4, 20, 32}.

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2 years ago

Verify that [tan(theta) + cot(theta)]^2 = sec^2(theta) + csc^2(theta)

Wittaler [7]

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2 years ago

The square root of 42. The answer needs to be simplified. The problem must be solved by using perfect squares. The answer can't

Rasek [7]

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3 years ago

Which of the following graphs of exponential functions corresponds to a geometric sequence with a first term of 4 and a ratio of

ser-zykov [4K]

Answer: graph E.

A geometric sequence can be written as:

$a_{n} = a_{1} \cdot r^{(n - 1)}$

where:

a₁ = first term = 4

r = ratio = 0.5

Substituting the numbers, we have:

$a_{n} = 4 \cdot (\frac{1}{2})^{n-1}$

or else

$f(x) = 4 \cdot (\frac{1}{2})^{x - 1}$

This is an exponential function with base less than 1. Therefore, we can exclude graph C (which depicts a linear function), and graphs A and D (which depict an exponential function with base greater than 1).

In order to choose between graph B and E, let's evaluate the function in two different points:

$f(1) = 4 \cdot (\frac{1}{2})^{1 - 1} = 4$

$f(2) = 4 \cdot (\frac{1}{2})^{2 - 1} = 4 \cdot \frac{1}{2} = 2$

Therefore, we need to look for the graph passing through the points (1, 4) and (2, 2). That is graph E.

3 0

2 years ago

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