Question

f(x)=x2+5x-4 has a domain D={-4,-2,0,3,5} find the range (f(x)) value for each x value in the domain

Answer 1

Answer:

The range here is the set {8, -10, -4, 20, 32}.

Step-by-step explanation:

Please use " ^ " to denote exponentiation.  Thanks.   f(x)=x^2 + 5x - 4

f(-4)=(-4)^2 + 5(-4) - 4  =  8

f(-2)=(-2)^2 + 5(-1) - 4   = -10

f(0)=0^2 + 5(0) - 4 = -4

f(3) =3^2 + 5(3) - 4      =   20

f(4)=4^2 + 5(4) - 4       = 32

In this problem we have to calculate the actual function values for the given domain (input values).  The range here is the set {8, -10, -4, 20, 32}.