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3 years ago

19 points if uu help meeee

Mathematics

2 answers:

Sindrei [870]3 years ago

8 0

Answer:

Step-by-step explanation:

Answer is sixteen. A squared plus B squared equals C squared.

A=15sq

B=6sq

C=Xsq

A=225

B=36

C=x

226 + 36 =261

261 = 16sq...roughly...

Answer is 16.

Hope this helps! I hope you do well on that test, we believe in you!

DochEvi [55]3 years ago

4 0

Answer:

It is 21

Step-by-step explanation:

It is not hard all you got to do is 25+6=21 hope it helps plz Mark me brainlest :)

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Can you help me figure this out please

Anna007 [38]

Answer:

C & D

Step-by-step explanation:

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3 years ago

An airplane started at point K, travelled 560 miles to point L, adjusted its route and travelled another 575 miles to point M. I

S_A_V [24]

Answer:

Step-by-step explanation:

Using the cosine theorem:

$c^{2} =a^{2} +b^{2} -abcos\beta$

$952^{2} =560^{2} +575^{2} -560*575cos\beta$

$\beta =cos^{-1} (\frac{560^{2}+575^{2}-952^{2} }{2*560*575} )$

The angle is 114.014 degrees if we substract 90 degrees it means that at point L the plane changed its angle by 24 degrees

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3 years ago

A right circular cone is undergoing a transformation in such a way that the radius of the cone is increasing at a rate of 1/2 in

Ivenika [448]

Answer:

The volume is decreasing at the rate of 1.396 cubic inches per minute

Step-by-step explanation:

Given

Shape: Cone

$\frac{dr}{dt} =\frac{1}{2}$ --- rate of the radius

$\frac{dh}{dt} =-\frac{1}{3}$ --- rate of the height

$r = 2$

$h = \frac{1}{3}$

Required

Determine the rate of change of the cone volume

The volume of a cone is:

$V = \frac{\pi}{3}r^2h$

Differentiate with respect to time (t)

$\frac{dV}{dt} = \frac{\pi}{3}(2rh \frac{dr}{dt} + r^2 \frac{dh}{dt})$

Substitute values for the known variables

$\frac{dV}{dt} = \frac{\pi}{3}(2*2*\frac{1}{3}* \frac{1}{2} - 2^2 *\frac{1}{3})$

$\frac{dV}{dt} = \frac{\pi}{3}(\frac{4}{3}* \frac{1}{2} - \frac{4}{3})$

$\frac{dV}{dt} = \frac{\pi}{3}(\frac{4}{3}(\frac{1}{2} - 1))$

$\frac{dV}{dt} = \frac{\pi}{3}(\frac{4}{3}*- 1)$

$\frac{dV}{dt} = -\frac{\pi}{3}*\frac{4}{3}$

$\frac{dV}{dt} = -\frac{22}{7*3}*\frac{4}{3}$

$\frac{dV}{dt} = -\frac{22}{21}*\frac{4}{3}$

$\frac{dV}{dt} = -\frac{88}{63}$

$\frac{dV}{dt} =-1.396in^3/min$

The volume is decreasing at the rate of 1.396 cubic inches per minute

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3 years ago

Application of linear equation in two variable in real life

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4 years ago

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A is the correct answer.

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3 years ago

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