<u>Function</u> <u>composition</u> is applying one function to the <u>results</u> of another:
This means the result of g() is sent through f(). Written notation for the composition is
Note that then
Since then
Answer:
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Answer:
Electric car = Exponential function (decreasing cost)
Gasoline car = Exponential function (increasing cost)
Step-by-step explanation:
The given data the Electric car, we have;
Time (years) Cost (thousands of dollars)
0 35
5 27
10 21
15 16
20 12.5
The difference between successive term is such that each term decreases by approximately the same percentage given as follows
1st and 2nd term (35 - 27)/35 × 100 ≈ 22.8571% decrease
2nd and 3rd term (27 - 21)/27 × 100 ≈ 22.222% decrease
3rd and 4th term (21 - 16)/21 × 100 ≈ 23.81% decrease
4th and 5th term (16 - 12.5)/16 × 100 ≈ 21.875% decrease
Therefore. the electric car is best approximated by exponential function
The given data the Gasoline car, we have;
Time (years) Cost (thousands of dollars)
0 35
5 40.2
10 46.3
15 53.2
20 61.2
The difference between successive term is such that each term increases by approximately the same percentage given as follows
1st and 2nd term (40.2 - 35)/35 × 100 ≈ 14.857% decrease
2nd and 3rd term (46.3 - 40.2)/40.2 × 100 ≈ 15.174% decrease
3rd and 4th term (53.2 - 46.3)/46.3× 100 ≈ 14.9% decrease
4th and 5th term (61.2 - 53.2)/53.2× 100 ≈ 15.03% decrease
Therefore. the Gasoline car is best approximated by exponential function
A. True. We see this by taking the highest order term in each factor:
B. True. Again we look at the leading term's degree and coefficient. f(x) behaves like -3x⁶ when x gets large. The degree is even, so as x goes to either ± ∞, x⁶ will make it positive, but multiplying by -3 will make it negative. So on both sides f(x) approaches -∞.
C. False. f(x) = 0 only for x=0, x = 5, and x = -2.
D. False. Part of this we know from the end behavior discussed in part B. On any closed interval, every polynomial is bounded, so that for any x in [-2, 5], f(x) cannot attain every positive real number.
E. True. x = 0 is a root, so f(0) = 0 and the graph of f(x) passes through (0, 0).
F. False. (0, 2) corresponds to x = 0 and f(x) = 2. But f(0) = 0 ≠ 2.