(xy)' + (2x)' + (3x^2)' = (4)'
y + xy' + 2 + 6x = 0
xy' = -y -2 -6x
y' = [-y -2 -6x] / x
Now solve y from the original equation and substitue
xy + 2x + 3x^2 = 4 => y = [-2x - 3x^2 + 4] / x
y' = [(-2x - 3x^2 +4) / x - 2 - 6x ] / x
y' = [-2x - 3x^2 + 4 -2x -6x^2 ] x^2 = [ -4x - 9x^2 + 4] / x^2 =
= [-9x^2 - 4x + 4] / x^2
Domain:-> ( (-infinity) ,4)
Range:-> ((-infinity),infinity)
increasing in (-2.8,1.4)
decrasing in ( (-infinity) ,-2.8 ) U (1.4, infinity)
Hope it helps...
Regards,
Leukonov/Olegion.
Yes he is right because 100/20 is 5 and 7 times 5 is 35%
Answer: c = -7
Step-by-step explanation:
-4 + c = -11
c = -7
