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pogonyaev
4 years ago
9

Write a division algebra equation that has a solution of 42

Mathematics
1 answer:
alina1380 [7]4 years ago
5 0
Here, we can do x/2 = 21. Multiply both sides by 2 to get x = 42. Hope this helps.
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Determine if the two figures are congruent and explain your answer.
Dvinal [7]
They are congruent. Distance formula works.
3 0
2 years ago
The point (-7,4) in on the terminal side of an angle t. Find sec (t) to two decimal places.
Sliva [168]

Answer:

  -1.15

Step-by-step explanation:

The tangent of the angle can be found as ...

  tan(t) = (y-coordinate)/(x-coordinate) = -4/7

The secant of the angle is related by ...

  sec(t)² = tan(t)² +1 = (-4/7)² +1 = 65/49

Then the secant of this 2nd-quadrant angle is ...

  sec(t) = -√(65/49) = -(√65)/7 ≈ -1.15

6 0
3 years ago
Solve: 3a - 2.4 = 5.1 a = _____
Delicious77 [7]

Answer:

a=2.5

Step-by-step explanation:

3a-2.4=5.1   Add the like terms ( plus 2.4 cancels out -2.4)

   +2.4  +2.4

3a=7.5  Now divide by 3

/3     /3

a=2.5

7 0
3 years ago
PLEASE HELP!!!! 20 POINTS!!!!
galben [10]
These are two questions and two answers.

Question 1) Which of the following polar equations is equivalent to the parametric equations below? 

<span> x=t²
y=2t</span>

Answer: option <span>A.) r = 4cot(theta)csc(theta)
</span>

Explanation:

1) Polar coordinates ⇒ x = r cosθ and y = r sinθ

2) replace x and y in the parametric equations:

r cosθ = t²
r sinθ = 2t

3) work r sinθ = 2t

r sinθ/2 = t 
(r sinθ / 2)² = t²

4) equal both expressions for t²

r cos θ = (r sin θ / 2 )²

5) simplify

r cos θ = r² (sin θ)² / 4

4 = r (sinθ)² / cos θ

r = 4 cosθ / (sinθ)²

r = 4 cot θ csc θ ↔ which is the option A.


Question 2) Which polar equation is equivalent to the parametric equations below?

<span> x=sin(theta)cos(theta)+cos(theta)
y=sin^2(theta)+sin(theta)</span>

Answer: option B) r = sinθ + 1


Explanation:

1) Polar coordinates ⇒ x = r cosθ, and y = r sinθ

2) replace x and y in the parametric equations:

a) r cosθ = sin(θ)cos(θ)+cos(θ)
<span> b) r sinθ =sin²(θ)+sin(θ)</span>

3) work both equations

a) r cosθ = sin(θ)cos(θ)+cos(θ) ⇒ r cosθ = cosθ [ sin θ + 1]  ⇒ r = sinθ + 1


<span> b) r sinθ =sin²(θ)+sin(θ) ⇒ r sinθ = sinθ [sinθ + 1] ⇒ r = sinθ + 1
</span><span>
</span><span>
</span>Therefore, the answer is r = sinθ + 1 which is the option B.
6 0
3 years ago
Read 2 more answers
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Basile [38]
The correct answer is $70,741 :)
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3 years ago
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