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poizon [28]
3 years ago
10

Find the distance between origin and a point -5,5​

Mathematics
1 answer:
nexus9112 [7]3 years ago
7 0
- 10 is the answer like the other person said I think. ?????
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Gregg’s average rate of speed is ________ miles per hour
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Divide the total distance traveled by the total time spent traveling. This will give you your average speed. S = 56.67 {\displaystyle S=56.67} . So if Ben traveled 50 mph for 3 hours, 60 mph for 2 hours, and 70 mph for 1 hour, his average speed was about 57 mph.

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For line graphs and bar graphs, the values measured by the ____axis depend on the values measured by the horizontal axis.
sveticcg [70]

Answer:

the correct answer will be vertical axis

Step-by-step explanation:

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3 years ago
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What are the dimensions (length and width) if the poster is enlarged by a factor of 1.5 ? (Remember multiply the factor by the d
Veseljchak [2.6K]
Use socratic or photomath
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3 years ago
If <img src="https://tex.z-dn.net/?f=tan%20%28x%29%20%3D%20%5Cfrac%7B5%7D%7B12%7D" id="TexFormula1" title="tan (x) = \frac{5}{12
Alekssandra [29.7K]

Explanation:

First, we need to find the values of the sine and cosine of x knowing the value of tan x and x being in the 3rd quadrant. Since tan x = 5/12, using Pythagorean theorem, we know that

\sin x = -\frac{5}{13}\;\;\text{and}\;\;\cos x = -\frac{12}{13}

Note that both sine and cosine are negative because x is in the 3rd quadrant.

Recall the addition identities listed below:

\sin(\alpha + \beta) = \sin\alpha\sin\beta + \cos\alpha\cos\beta

\Rightarrow \sin(180+x) = \sin180\sin x + \cos180\cos x

\;\;\;\;\;\;= -\sin x = \dfrac{5}{13}

\cos(\alpha - \beta) = \cos\alpha \cos\beta + \sin\alpha \sin\beta

\Rightarrow \cos(180 - x) = \cos180\cos x + \sin180\sin x

\;\;\;\;\;\;=-\cos x = \dfrac{12}{13}

\tan(\alpha - \beta) = \dfrac{\tan\alpha - \tan\beta}{1 + \tan\alpha\tan\beta}

\Rightarrow \tan(360 - x) = \dfrac{\tan 360 - \tan x}{1 + \tan 360 \tan x}

\;\;\;\;\;\;= -\tan x = -\dfrac{5}{12}

Therefore, the expression reduces to

\sin(180+x) + \tan(360-x) + \frac{1}{\cos(180-x)}

\;\;\;\;\;= \left(\dfrac{5}{13}\right) + \left(\dfrac{5}{12}\right) + \dfrac{1}{\left(\frac{12}{13}\right)}

\;\;\;\;\;= \dfrac{49}{26}

5 0
3 years ago
Geo please help I have two question!
cricket20 [7]

Answer:

Step-by-step explanation:

From the given right angle triangle,

the hypotenuse of the right angle triangle is 13

With m∠65° as the reference angle,

y represents the adjacent side of the right angle triangle.

x represents the opposite side of the right angle triangle.

To determine the value of x, we would apply the sine trigonometric ratio which is expressed as

Sin θ = opposite side/hypotenuse. Therefore,

Sin 65 = x/13

x = 13Sin65 = 13 × 0.906

x = 11.8 to the nearest tenth

8 0
4 years ago
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