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3 years ago

Which statement describes the symmetry of the data in the two box plots?

Mathematics

2 answers:

laila [671]3 years ago

7 0

Answer:the data in country B are more symmetric than the data in country A.

Step-by-step explanation:

inysia [295]3 years ago

3 0

Answer:

The data in country B are more symmetric than the data in country A.

Step-by-step explanation:

The following information is missing:

The box plots show the average wind speeds, in miles per hour, for various cities in two different countries. Average Wind Speeds of Cities in Country A 2 box plots. The number line goes from 1 to 11. For the average wind speeds of cities in country A, the whiskers range from 1 to 9.5, and the box ranges from 3 to 7. A line divides the box at 4. For the average wind speeds of cities in country B, the whiskers range from 1.2 to 11, and the box ranges from 4 to 9. A line divides the box at 6. Average Wind Speeds of Cities in Country B

Country A

minimum: 1

quartile 1: 3

median: 4

quartile 3: 7

maximum: 9.5

Country B

minimum: 1.2

quartile 1: 4

median: 6

quartile 3: 9

maximum: 11

We can see that the difference between quartile 1 and minimum, median and quartile 1, quartile 3 and median, and maximum and quartile 3 is more homogeneous in Country B than Country A, then Country B is more symmetric.

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Nine to the yth power?

iren [92.7K]

Answer:

9^y

Step-by-step explanation:

the way u write nine to the yth power, if y is something meet me in the comments!!

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3 years ago

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ANTONII [103]

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2 years ago

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Find the value of a: a(x+3)<5x+15-x a=

Vinil7 [7]

Answer:

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Step-by-step explanation:

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Ratling [72]

Answer:

$P(X>10.983)=P(\frac{X-\mu}{\sigma}>\frac{10.983-\mu}{\sigma})=P(Z>\frac{10.983-10.5}{0.3})=P(z>1.61)$

And we can find this probability using the complement rule and with excel or the normal standard table:

$P(z>1.61)=1-P(z$

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".

Solution to the problem

Let X the random variable that represent the weights of a population, and for this case we know the distribution for X is given by:

$X \sim N(10.5,0.3)$