3 years ago

Please help me please

Mathematics

1 answer:

maxonik [38]3 years ago

8 0

Answer:

Step-by-step explanation:

Hopefully this helps

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Solve (x – 4)^2=5<br> Hhhhhbb

Oxana [17]

Answer:

x = 4 + sqrt(5) or x = 4 - sqrt(5)

Step-by-step explanation:

Solve for x:

(x - 4)^2 = 5

Take the square root of both sides:

x - 4 = sqrt(5) or x - 4 = -sqrt(5)

Add 4 to both sides:

x = 4 + sqrt(5) or x - 4 = -sqrt(5)

Add 4 to both sides:

Answer: x = 4 + sqrt(5) or x = 4 - sqrt(5)

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Answer:3

Step-by-step explanation:

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The normal temperature range for Yuma, AZ on January 11 is at least 48 degrees but no higher than 64 degrees Fahrenheit. Which i

WITCHER [35]

Answer: Our required interval for temperature is $48\leq x\leq 64$

Step-by-step explanation:

Since we have given that

The normal temperature range for Yuma, on Janurary is atleast = 48 degrees

and the highest temperature on that day is no higher than 64 degrees.

Let the temperature in Yuma be 'x'.

So, we know that for atleast means it can 48 degrees or more, and no higher than means it should be equa to or less than 64 degrees.

Mathematically, it is expressed as

$48\leq x\leq 64$

Hence, our required interval for temperature is $48\leq x\leq 64$

7 0

3 years ago

Please help me please ​

Please help me please