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larisa86 [58]
3 years ago
7

Are the triangles congruent? Why or why not?

Mathematics
2 answers:
77julia77 [94]3 years ago
8 0
The correct answer is:

Yes, they are congruent by either ASA or AAS. 

We know one side is congruent with the marking, and two angles are at least congruent. 

I hope this helps!
~kaikers
balu736 [363]3 years ago
7 0
Triangle ABC
unknown angle = 180 - 42 - 53 = 85
so measure of angles in triangle ABC: 42, 53, 85

triangle RMQ
unknown angle = 180 - 42 - 85 = 53
so measure of angles in triangle RMQ: 42, 53, 85

both triangles are <span>congruent

answer
</span><span>Yes, all the angles of each of the triangles are acute.</span>
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Evgen [1.6K]

Answer:

b = 39

Step-by-step explanation:

The two sides are equivalent so we can use this information to form an equation.

2b - 39 = b

-39 = -b

39 = b

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3 years ago
A wall in Maria’s bedroom is in the shape of a trapezoid. The wall can be divided into a rectangle and a triangle.
igor_vitrenko [27]

Answer:

13 foot

Step-by-step explanation:

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2 years ago
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Write four numbers that fall between 0.123 and 0.124
irga5000 [103]
That's what I think but if im wrong im sorry:
0.123-0.1231,0.1232, 0.1233, 0.1234-0.124
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2 years ago
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yanalaym [24]

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3 years ago
If 1200 cm2 of material is available to make a box with a square base and an open top, find the largest possible volume of the b
Colt1911 [192]

Answer:

The largest possible volume V is ;

V = l^2 × h

V = 20^2 × 10 = 4000cm^3

Step-by-step explanation:

Given

Volume of a box = length × breadth × height= l×b×h

In this case the box have a square base. i.e l=b

Volume V = l^2 × h

The surface area of a square box

S = 2(lb+lh+bh)

S = 2(l^2 + lh + lh) since l=b

S = 2(l^2 + 2lh)

Given that the box is open top.

S = l^2 + 4lh

And Surface Area of the box is 1200cm^2

1200 = l^2 + 4lh ....1

Making h the subject of formula

h = (1200 - l^2)/4l .....2

Volume is given as

V = l^2 × h

V = l^2 ×(1200 - l^2)/4l

V = (1200l - l^3)/4

the maximum point is at dV/dl = 0

dV/dl = (1200 - 3l^2)/4

dV/dl = (1200 - 3l^2)/4 = 0

3l^2= 1200

l^2 = 1200/3 = 400

l = √400

I = 20cm

Since,

h = (1200 - l^2)/4l

h = (1200 - 20^2)/4×20

h = (800)/80

h = 10cm

The largest possible volume V is ;

V = l^2 × h

V = 20^2 × 10 = 4000cm^3

4 0
2 years ago
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