Answer:
The GCF for the numerical part is 2
Step-by-step explanation:
6x^2y^2-8xy^2+10xy
It contains both numbers and variables, there are two steps to find the GCF(HCF).
1). Find the GCF for the numerical part 6, -8,10
2). Find the GCF for the variable part x^2,y^2,x^1,y^2,x^1,y^3
3).Multiply the values together.
Find the common factors for the numerical part:
6,-8,10
Factors of 6
6: 1,2,3,6
Factors of -8
-8: -8,-4,-2,-1,1,2,4,8
Factors of 10
10:1,2,5,10
Common factors of 6,-8, 10 are 1,2
The GCF Numerical=2
The GCF Variable= xy^2
Multiply the GCF of the numerical part 2 and the GCF of the variable part xy^2, and you'll get 2xy^2
For the first Listing Exercise:
(NOT A)
1. 5x + 65 = 5(x + 13) because if you apply distributive property to the one from List B, it would equal the same as List A's answer.
2. 5(x + 1) = 5x + 5 because if you apply distributive property to the equation from List A, it would equal the same as the one from List B.
3. 1 + 5x = 5x + 1 because this is simple commutative property.. switching the placements.
To solve this problem you must apply the following proccedure:
1. You have a total of 21 coins, all nickels and dimes. Then:
x:nickels=5 cents
y: dimes=10 cents
x+y=21
2. You have that the total value is $1.70. Then:
5x+10y=170
3. The system of equation is:
x+y=21 (i)
5x+10y=170 (ii)
4. You have:
x+y=21
x=21-y
5(21-y)+10y=170
105-5y+10y=170
y=13 dimes
x+13=21
x=8 nickels
Answer:
B is correct
Step-by-step explanation:
This is not an example of principle of independence
Answer:
23) 36·(3·1/4) = 36·(3/4) = 108/4 = 27
24) (4·2/7)·21 = (8/7)·21 = 168/7 = 24
25) 2(x+4) = 2x+8
26) (5+n)3 = 15+3n
27) (4-3m)8 = 32-24m
28) -3(2x-6) = -6x+18
29) 13r+5r = 18r
30) 3x³-2x²
31) 7m+7-5m = 2m+7
32) 5z²+3z+8z² = 3z+13z²
33) (2-4n)17 = 34-68n
34) 11(4d+6) = 44d+66
35) 7m+2m+5p+4m = 13m+5p
36) 3x+7(3x+4) = 3x+21x+28 = 24x+28
37) 4(fg+3g)+5g = 4fg+12g+5g = 4fg+17g
38) (5m)²+(m+5)²= 26m²+10m+25
39) 7(a²+b)-4(a²+b) = 3(a²+b) = 3a²+b
