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aleksandr82 [10.1K]
1 year ago
5

james brewer purchased 100 shares of stock for $73 a share. james also paid a $60 commission. what was the total purchase price

for this transaction?
Mathematics
2 answers:
drek231 [11]1 year ago
7 0

Answer:

$ 7360.00

Step-by-step explanation:

100 shares   *   $ 73/share   + $60  = $ 7360

Ulleksa [173]1 year ago
5 0

Based on the calculation below,  the total purchase price for this transaction is $7,360.

<h3>How do we calculate the total purchase price of shares of stock?</h3>

The total purchase price for this transaction can be calculated using the following formula:

Total purchase price = (Price per share * Units of shares purchased) + Commission ...................................... (1)

Substituting all the values into equation (1), we have:

Total purchase price = ($73 * 100) + $60 = $7,360

Learn more about share purchases here: brainly.com/question/20490753.

#SPJ11

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A large company increased its sales from last year to this year by 34%.
AlexFokin [52]

Given:

The last year sales = $288,000,000

Company increased its sales from last year to this year by 34%.

To find:

The this year's sales to the nearest million dollars.

Solution:

We have,

The last year sales = $288 million

The company increased its sales from last year to this year by 34%. So,

This year's sales =288+288\times \dfrac{34}{100}

                            =288+97.92

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Therefore, this year's sales were 386 million dollars or $386,000,000.

8 0
3 years ago
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Juliette [100K]

Answer:

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3 years ago
Suppose a particular type of cancer has a 0.9% incidence rate. Let D be the event that a person has this type of cancer, therefo
natita [175]

Answer:

There is a 12.13% probability that the person actually does have cancer.

Step-by-step explanation:

We have these following probabilities.

A 0.9% probability of a person having cancer

A 99.1% probability of a person not having cancer.

If a person has cancer, she has a 91% probability of being diagnosticated.

If a person does not have cancer, she has a 6% probability of being diagnosticated.

The question can be formulated as the following problem:

What is the probability of B happening, knowing that A has happened.

It can be calculated by the following formula

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Where P(B) is the probability of B happening, P(A/B) is the probability of A happening knowing that B happened and P(A) is the probability of A happening.

In this problem we have the following question

What is the probability that the person has cancer, given that she was diagnosticated?

So

P(B) is the probability of the person having cancer, so P(B) = 0.009

P(A/B) is the probability that the person being diagnosticated, given that she has cancer. So P(A/B) = 0.91

P(A) is the probability of the person being diagnosticated. If she has cancer, there is a 91% probability that she was diagnosticard. There is also a 6% probability of a person without cancer being diagnosticated. So

P(A) = 0.009*0.91 + 0.06*0.991 = 0.06765

What is the probability that the person actually does have cancer?

P = \frac{P(B).P(A/B)}{P(A)} = \frac{0.91*0.009}{0.0675} = 0.1213

There is a 12.13% probability that the person actually does have cancer.

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