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Leokris [45]
3 years ago
11

Social participation is the backbone of socialization. Justify the statement.​

Social Studies
1 answer:
yulyashka [42]3 years ago
4 0

Answer:

Yes

Explanation:

social participation is the backbone of socialization as it is an initiative to involve in societal activities.

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I say just talk it out communication is everything
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Will genetic engineering help or hurt people? Why?
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I'm guessing It could do both but I'm going more with hurting
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Gabe was essentially fluent in French in elementary school when he lived in Canada, but then moved away until he got a job offer
Makovka662 [10]

Answer:

This is an example of recall.

Explanation:

Recalling is the action of bringing information back from the long-term memory, which has been previously stored.

Once information is stored in this type of memory, it won't be forgotten with ease and can be accessible by cues, for example.

Since Gabe was still in elementary school when he learnt French, it was easier for him to retain this information. Now, once he heads to Paris and listens to French again, it is easier for him to access the previously learnt information since the language itself provided him with the cues he needed to do so.

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4 years ago
Can you manually light a gas fireplace with electronic ignition.
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Answer:yes

Explanation:

5 0
2 years ago
A basketball is dropped from the edge of a cliff at the same time that second basketball is thrown upward from the ground. When
pentagon [3]

Answer:

The collision occurs at a height of 1/3 of the total height of cliff.

Explanation:

The situation is represented in the attached figure:

For the stone dropped from top of cliff we have

Initial velocity of drop= 0 m/s.

Now the time at which it attains a velocity of 2v is obtained from first equation of kinematics as

v_{f}=u_{i}+gt\\\\2v=0+gt\\\\\therefore t=\frac{2v}{g}

Thus the distance it covers in this time can be calculated using third equation of kinematics as

v_{f}^{2}=v_{i}^{2}+2gh\\\\(2v)^{2}=2gh_{1}\\\\\therefore h_{1}=\frac{2v^{2}}{g}

For the stone thrown upwards the velocity at collision is give as 'v' thus the velocity at which it is thrown upwards can be calculated by first equation of kinematics as

v=v_{i}-gt\\\\\therefore v_{i}=v+gt\\\\v_{i}=v+g\times \frac{2v}{g}\\\\\therefore v_{i}=3v

The height over which it changes it's velocity from '3v' to 'v' can be again obtained from third equation of kinematics as

v^{2}=(3v)^{2}-2gh_{2}\\\\v^{2}=9v^{2}-2gh_{2}\\\\\therefore h_{2}=\frac{4v^{2}}{g}

\therefore h_{2}=2h_{1}

Thus the collision occurs at at a fraction of 1/3 of height.

6 0
3 years ago
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