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2 years ago

I don’t understand can someone help me

Mathematics

1 answer:

Elden [556K]2 years ago

6 0

You set 49 equal to 8x - 15

So

8x - 15 = 49
+15 + 15

8x = 64

Then divide by 8

X= 8

You might be interested in

Rewrite as a power <br> 1 7/9

Morgarella [4.7K]

Answer:

$1\frac{7}{9} =\frac{16}{9} =[\frac{4}{3}] ^{2}$

Step-by-step explanation:

6 0

3 years ago

A linear equation has more than one intercept. what can you conclude about the graph of the equation?

DanielleElmas [232]

A linear equation of the form :

y = mx+b

can have at the most ONE x-intercept and at the most ONE y-intercept

I can conclude that this linear equation DOESN'T pass through the origin (O) and that it intercepts the x-axis as well as the y-axis

5 0

2 years ago

ILL GIVE BRAINLIEST ON THIS QUESTION!!!!!!!!!!!!!!!!!!!!!!!!!!!

DochEvi [55]

Answer:

15.25 or 15 if you need it to be rounded.

Step-by-step explanation:

-11 on both sides to get 5x=1x+61. Then, -1x on both sides to get 4x=61. Then to find x you do 61 divided by 4 which is 15.25.

8 0

2 years ago

Let a, b, c, and d be real numbers with a, c 6= 0. Prove that the lines y = ax+b and y = cx + d have the same x-intercept if and

Monica [59]

Step-by-step explanation:

We have got the lines :

$y=ax+b\\y=cx+d$

Both lines intercept the x-axis in the point :

$I = (i_{1} ,i_{2})$

In all point from x-axis the y-component is equal to 0.

$I=(i_{1},o)$

We replace the I point in the lines equations:

$0=a(i_{1})+b \\0=c(i_{1})+d$

From the first equation :

$0=a(i_{1})+b \\-b=a(i_{1})\\i_{1}=\frac{-b}{a}$

From the second equation :

$0=c(i_{1})+d\\ -d=c(i_{1})\\i_{1}=\frac{-d}{c}$

Then $i_{1}=i_{1}$

Finally :

$\frac{-b}{a}=\frac{-d}{c} \\\frac{b}{a}=\frac{d}{c} \\ad=bc$

y = ax + b and y = cx + d have the same x-intercept ⇔ad=bc

8 0

3 years ago

<img src="https://tex.z-dn.net/?f=if%20%5C%3A%20%28%20%5Cfrac%7B3%7D%7B4%7D%20%29%5E%7B6%7D%20%20%5Ctimes%20%28%20%5Cfrac%7B16%7

zhenek [66]

Answer:

Step-by-step explanation:

$(\frac{3}{4})^6 \times (\frac{16}{9})^5=(\frac{4}{3})^{x+2}$

$\frac{3^6}{4^6} \cdot \frac{16^5}{9^5}=\frac{4^{x+2}}{3^{x+2}}$

$\frac{3^6}{4^6} \cdot \frac{(4^2)^5}{(3^2)^5}=\frac{4^{x+2}}{3^{x+2}}$

$\frac{3^6}{4^6} \cdot \frac{4^{10}}{3^{10}}=\frac{4^{x+2}}{3^{x+2}}$

$\frac{3^6}{3^{10}} \cdot \frac{4^{10}}{4^6}=\frac{4^{x+2}}{3^{x+2}}$

$3^{-4} \cdot 4^{4}=4^{x+2}3^{-(x+2)}$

This implies

x+2=4

and

-(x+2)=-4.

x+2=4 implies x=2 since subtract 2 on both sides gives us x=2.

Solving -(x+2)=-4 should give us the same value.

Multiply both sides by -1:

x+2=4

It is the same equation as the other.

You will get x=2 either way.

Let's check:

$(\frac{3}{4})^6 \times (\frac{16}{9})^5=(\frac{4}{3})^{2+2}$

$(\frac{3}{4})^6 \times (\frac{16}{9})^5=(\frac{4}{3})^{4}$

Put both sides into your calculator and see if you get the same thing on both sides:

Left hand side gives 256/81.

Right hand side gives 256/81.

Both side are indeed the same for x=2.

4 0

3 years ago