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3 years ago

Which of the following stories represents the fraction 16/5?

Mathematics

2 answers:

Novay_Z [31]3 years ago

6 0

Answer is to your question is A

Rzqust [24]3 years ago

4 0

D) Sixteen people share 5 slices of pizza.

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Simplify: x(x-2)-3x(2x-1)

julsineya [31]

Answer:

-5x^2 +x

Step-by-step explanation:

x(x-2)-3x(2x-1)

Distribute

x^2 -2x -6x^2 +3x

Combine like terms

-5x^2 +x

4 0

3 years ago

Read 2 more answers

Help me please and thanks

Stels [109]

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Bolded are your answers. The others are if i missed some of the choices. To have a triangle name, it must all be angles, and no side lengths.

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3 0

4 years ago

Read 2 more answers

For a store contest, four out of every 65 people who visit the store will receive a free DVD. If 455 people visit the store, how

Zolol [24]

Maybe try 455 / 65??

8 0

3 years ago

A new soup recipe contains 33 percent less sodium per serving than the old soup recipe. The old soup recipe contained x milligra

masya89 [10]

Answer:

The expressions that could represent the amount of sodium per serving, in milligrams, in the new soup recipe is a) 0.67x

Step-by-step explanation:

Given:

A new soup recipe contains 33 percent less sodium per serving than the old soup recipe. The old soup recipe contained x milligrams of sodium per serving.

Now, to find the expression that could represent the amount of sodium per serving, in milligrams, in the new soup recipe.

The old soup recipe contained sodium per serving = $x\ milligrams.$

As given, the new soup recipe contains 33 percent less sodium per serving than the old soup recipe.

So, to get the amount of new soup recipe sodium per serving we write an equation:

$x-33\%\ of\ x$

= $x-\frac{33}{100} \times x$

= $x-\frac{33x}{100}$

= $x-0.33x$

= $0.67x.$

Thus, the expression $0.67x$ milligrams represent the amount of sodium per serving in new soup recipe.

Therefore, the expressions that could represent the amount of sodium per serving, in milligrams, in the new soup recipe is a) $0.67x.$

5 0

3 years ago

A manufacturing machine has a 10% defect rate.If 4 items are chosen at random, what is the probability that at least one will ha

vagabundo [1.1K]

Solution

Step 1

$\begin{gathered} probability\text{ of defective p = 10\% = }\frac{10}{100}\text{ = 0.1} \\ \\ probability\text{ of not defective q = 1 - p = 1 - 0.1 = 0.9} \\ \end{gathered}$

Step2

The probability that at least one will have a defect

= 1 - the probability that noon will have a defect

Step 3

Use the binomial distribution

$\begin{gathered} =1\text{ - }^nC_rp^rq^{n-r} \\ n\text{ = 4, r = 0} \\ \\ =1-^4C_0(0.1)^0(0.9)^{4-0} \\ \\ =\text{ 1 - 1}\times1\times0.9\times0.9\times0.9\times0.9 \\ \\ =\text{ 0.344} \end{gathered}$

8 0

2 years ago