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4 years ago

Of the 600 workers at a factory, 8.5% belong to a union. how many workers are in the union?

Mathematics

2 answers:

worty [1.4K]4 years ago

4 0

600X8.5=5100
5100/100=51
Answer=51

Mazyrski [523]4 years ago

3 0

51 workers are in the union

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bezimeni [28]

Answer:

The answer is A

Step-by-step explanation:

The answer is A because if you flip it over the y-axis it will be on the same line as before.

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3 years ago

Celia writes the addition problem shown.she says she can tell which sum will be greater without adding.how does she know?

kobusy [5.1K]

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3 years ago

Which expressions are equivalent to -5x - 15 + 25x - 30? Choose ALL that apply. −5(2 − 3+52 – 6) −5(2 – 5x + 9) −5(2+3 – 5x – 6)

timurjin [86]

The correct expression that is equivalent to the algebraic expression -5x - 15 + 25x - 30 is -5(-4x + 9).

<h3>How to determine the equivalent expression</h3>

We shall simplify the given algebraic expression by carrying out basic mathematics operations as follows;

Given: -5x - 15 + 25x - 30

we group like terms together

25x - 5x - 15 - 30

20x - 45

the number 5 is a common factor of 20x and 45, so we have that;

5 × 4x - 5 × 9

by factoring out 5

5(4x - 9)

also;

5(4x - 9) = -5(-4x + 9)

Therefore, -5(-4x + 9) is an equivalent expression to the algebraic expression -5x - 15 + 25x - 30

Learn more about equivalent expression here: brainly.com/question/24734894

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1 year ago

Indicate the equation of the given line in standard form. The line that is the perpendicular bisector of the segment whose endpo

noname [10]

Well the line that bisects RS, will cut RS in two equal halves, therefore, that line will cut RS perpendicularly at the midpoint of RS.

now, what the dickens is the midpoint of RS anyway?

$\bf \textit{middle point of 2 points }\\ \quad \\
\begin{array}{lllll}
&x_1&y_1&x_2&y_2\\
% (a,b)
R&({{ -1}}\quad ,&{{ 6}})\quad 
% (c,d)
S&({{ 5}}\quad ,&{{ 5}})
\end{array}\qquad
% coordinates of midpoint 
\left(\cfrac{{{ x_2}} + {{ x_1}}}{2}\quad ,\quad \cfrac{{{ y_2}} + {{ y_1}}}{2} \right)
\\\\\\
\left( \cfrac{5-1}{2}~~,~~\cfrac{5+6}{2} \right)\implies \stackrel{midpoint}{\left(2~~,~~\frac{11}{2} \right)}$

so, we know that perpendicular line, will have to go through (2, 11/2)

now, a perpendicular line to RS, will have a negative reciprocal slope to it. Well, what is the slope of RS anyway?

$\bf \begin{array}{lllll}
&x_1&y_1&x_2&y_2\\
% (a,b)
&({{ -1}}\quad ,&{{ 6}})\quad 
% (c,d)
&({{ 5}}\quad ,&{{ 5}})
\end{array}
\\\\\\
% slope = m
slope = {{ m}}= \cfrac{rise}{run} \implies 
\cfrac{{{ y_2}}-{{ y_1}}}{{{ x_2}}-{{ x_1}}}\implies \cfrac{5-6}{5-(-1)}\implies \cfrac{5-6}{5+1}\implies -\cfrac{1}{6}$

and let's check the reciprocal negative of that,

$\bf \textit{perpendicular, negative-reciprocal slope for slope}\quad -\cfrac{1}{6}\\\\
slope=-\cfrac{1}{{{ 6}}}\qquad negative\implies +\cfrac{1}{{{ 6}}}\qquad reciprocal\implies + \cfrac{{{ 6}}}{1}\implies 6$

so, then, what's is the equation of a line whose slope is 6, and goes through 2, 11/2?

$\bf \begin{array}{lllll}
&x_1&y_1\\
% (a,b)
&({{ 2}}\quad ,&{{ \frac{11}{2}}})
\end{array}
\\\\\\
% slope = m
slope = {{ m}}= \cfrac{rise}{run} \implies 6
\\\\\\
% point-slope intercept
\stackrel{\textit{point-slope form}}{y-{{ y_1}}={{ m}}(x-{{ x_1}})}\implies y-\cfrac{11}{2}=6(x-2)
\\\\\\
y-\cfrac{11}{2}=6x-12\implies -6x+y=-12+\cfrac{11}{2}\implies \stackrel{\textit{standard form}}{-6x+y=-\cfrac{13}{2}}$

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3 years ago

Which of these sentences best describes verbal irony?

gayaneshka [121]

Answer: the answer is B i think

Step-by-step explanation:

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3 years ago

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