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3 years ago

PLS help timed! which graph represents the solution of y<x2-1 and x>y2-3?

Mathematics

2 answers:

miv72 [106K]3 years ago

5 0

Answer:

y minus 3 = 2x plus 1

Step-by-step explanation:

allsm [11]3 years ago

5 0

Answer:

Graph the line using a y-intercept -1 and slope 1.

Graph the equation with vertex (0,0) and radius 2.

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What is nine thousand one hundred forty five divided by 3

Galina-37 [17]

Answer:

3,315 is the answer

Step-by-step explanation:

1) Just divide

9945 ÷ 3 = 3,315

Not hard

But here my answer!

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3 years ago

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If angle 1=22° and arch AD=57° then what is angle 2?

Sphinxa [80]

You should ask your parent/guardian
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3 years ago

Miyoko's goal is to earn more than \$950$950dollar sign, 950 this week. She earns \$250$250dollar sign, 250 for every day she wo

GrogVix [38]

$250 c+ $ 180 g > $ 950

<u>Step-by-step explanation:</u>

As a cryptographer (c), Miyoko earns per day = $ 250

As a geologist (g) , Miyoko earns per day = $ 180

So the equation comes to be $250 c+ $ 180 g = $ 950

The equation can be rewritten to find c as, (950-180 g) / 250

The equation can be rewritten to find g as, (950 - 250 c) / 180

Plugin different values of c and g in the above 2 equations, we can find that ,

To achieve the goal, Miyoko requires to be a geologist for 3 days and crpytographist for 2 days.

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3 years ago

Applying properties of Exponents in exercise,use the properties of exponents to simplify the expression.See example 1.

evablogger [386]

Answer: a) 15625, b) 0.2, c) 625, d) 0.008.

Step-by-step explanation:

Since we have given that

a) $(5^2)(5^3)$

As we know that

$a^m\times a^n=a^{m+n}$

So, it becomes,

$5^2\times 5^3=5^{2+3}=5^6=15625$

(b) $(5^2)(5^{-3})$

So, it becomes,

$5^2\times 5^{-3}=5^{2-3}=5^{-1}=\dfrac{1}{5}=0.2$

As we know that

$(a^m)^n=a^{mn}$

So, it becomes,

$5^{2\times 2}=5^4=625$

(d) $5^{-3}$

$a^{-m}=\dfrac{1}{a^m}\\\\5^{-3}=\dfrac{1}{5^3}=\dfrac{1}{125}=0.008$

Hence, a) 15625, b) 0.2, c) 625, d) 0.008.

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3 years ago

Find the tangent of ∠I.

Nady [450]

Answer:

tanI = $\frac{\sqrt{70} }{5}$

Step-by-step explanation:

We require to calculate GH using Pythagoras' identity in the right triangle.

GH² + GI² = HI²

GH² + 5² = ( $\sqrt{95}$ )²

GH² + 25 = 95 ( subtract 25 from both sides )

GH² = 70 ( take square root of both sides )

GH = $\sqrt{70}$

Then

tanI = $\frac{opposite}{adjacent}$ = $\frac{GH}{GI}$ = $\frac{\sqrt{70} }{5}$

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3 years ago

PLS help timed! which graph represents the solution of y<x2-1 and x>y2-3?​

PLS help timed! which graph represents the solution of y<x2-1 and x>y2-3?