Question

HELP ASAP!!! WILL GIVE BRAINLIEST! THESE FOUR QUESTIONS PLEASE!

Answer 1

1. 12.992 L

2. 2.42 moles

3. 275.52 L

4. 567.844 g

Further explanation

Given

moles and volume at STP

Required

mass, volume and moles

Solution

Conditions at T 0 ° C and P 1 atm are stated by STP (Standard Temperature and Pressure). At STP, Vm is 22.4 liters / mol.

1. 0.58 moles ammonia :

Volume = 0.58 moles x 22.4 L = 12.992 L

2. 77.5 grams of O₂ :

Moles = 77.5 grams x (1 mol/32 grams) = 2.42

3. 12.3 mole of Bromine gas :

Volume = 12.3 mole   x (22.4 L/1 mole) = 275.52 L

4. 4.8 moles iron(II)chloride :

Mass = 4.48 moles x molar mass ( 126,751 g/mol) = 567.844 g