You must know the concentration of the acetic acid. Suppose the concentration is 0.1 M. The solution is as follows:
CH₃COOH → CH₃COO⁻ + H⁺
I 0.1 0 0
C -x +x +x
E 0.1 - x x x
Ka = (x)(x)/(0.1 - x)
1.8×10⁻⁵ = x²/(0.1 - x)
Solving for x,
x = 1.333×10⁻³ = H⁺
pH = -log[H⁺] = -log(1.333×10⁻³)
pH = 2.88
Answer:
See explanation below.
Explanation:
In the equation ∆G = –nFE, E is the electromotive force ( cell potential ) in Volts.
Now in turn a Volt is defined as the potential difference that will impart one joule of energy per coulomb of charge that moves through two points.
V = J/C where J is Joules and C is coulombs of charge
Therefore in terms of units the equation will give us units of Joules:
[ mol] x [C/mol] x [J/C] = [J]
Answer:
the chocolate
Explanation:
You are changing the amount of chocolate
Two molecules that can cross a lipid bilayer without help from membrane proteins are oxygen and carbon dioxide. The property that allows this to happen is that both oxygen and carbon dioxide molecules are nonpolar which means that they can pass easily through the hydrophobic part of the membrane. The lipid bilayer is present in all cell membranes. It consists of two layers of the fat cells which are arranged into two sheets. It functions as a barrier which marks the boundaries of the cell. The inner part of a lipid bilayer is nonpolar since it is composed of the hydrophobic end of the phospholopids.
<span>Answer: Potassium hydroxide, KOH, is considered a BASE in an acid-base reaction because it ACCEPTS a hydrogen ion from the other reactant.
According to </span><span>Brønsted–Lowry acid–base theory, Base is a specie which accepts proton (H</span>⁺) while, Acid is a specie which donate proton.
Bases may contain a negative charge or lone pair of electrons, while, Acids contain positive charge or a neutral atom with incomplete octet.
In given statement KOH is acting as a base because it contains a negatively charged hydroxyl group which can accept proton from a acid, i.e.
KOH → K⁺ + OH⁻
Reaction of OH⁻ with any acid,
K⁺ + OH⁻ + HCl → H₂O + KCl
