Classify each of the following particulate level illustrations as a representation of either a pure substance, a homogeneous mix
ture, or a heterogeneous mixture.Figure:three compounds were drawn
1 answer:
Answer:
The classification and illustrations are attached in the drawing.
Explanation:
It is possible to identify the pure substance observing the figure, since it is the only one that has 2 joined atoms (purple and blue) which forms a single compound.
On the other hand, the homogeneous mixture is identified by noting that its atoms are more united with respect to the heterogeneous mixture, highlighting that in homogenous mixtures the atoms, elements or substances are not visible to the naked eye and are in a single phase, instead in the heterogeneous mixture if they can be differentiated.
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Answer:- 0.0211 moles of air.
Solution:- This problem is based on an ideal gas law equation.
temperature, pressure and volume are given and asked to calculate the moles of the air. Standard pressure is 1.00 atm.
T = 15 + 273 = 288 K
P = 1.00 atm
V = 0.500 L
The ideal gas law equation is, PV = nRT
where R is the universal gas law constant and its value is 0.0821 atm.L per mol per K.
n is the number of moles and its what we are asked to calculate.
For n, the equation is rearranged as:
Let's plug in the values and do the calculations:
n = 0.0211 moles
So, there are 0.0211 moles of the air in the bottle.