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Vedmedyk [2.9K]
3 years ago
11

A transformation is applied to the smaller triangle, A, to

Mathematics
1 answer:
Sergio039 [100]3 years ago
8 0

Answer:  dilation

Step-by-step explanation:

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Anna007 [38]

Answer:

Step-by-step explanation:

b/c we know that these triangles both have equal sides... that is given that <u>ab</u> and<u> be</u> are the same length.   and that <u>be </u>and <u>cd</u> are parallel , we know that they both are isosceles triangles and that the base angles are the same.  The side on <u> ad </u>and<u> ae</u>  have equal angles.

so we can make the equation

2a +56 = 180  (b/c we know that around a triangle it's 180°

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Expand the polynomial (x2 − y2)2 + (2xy)2, then simplify it by combining like terms.
Vlada [557]
<span><span>2<span>x^2</span></span>+<span><span>4x</span>y</span></span>−<span>2<span>y^<span>2
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3 years ago
John put 5 identical pairs of white socks and 5 identical pairs of black socks in the dryer. If he reaches in and grabs some soc
djyliett [7]

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Zielflug [23.3K]

Answer:

option 4.

16 square units

Step-by-step explanation:

as we do not have the measures of the sides, but if the points of the vertices with Pythagoras we can calculate the sides.

P = (2 , 4)

S = (4 , 2)

we have to subtract the values ​​of p from s

PS = (4 - 2  , 2 - 4)

PS = (2 , -2)

by pitagoras h ^ 2 = c1 ^ 2 + c2 ^ 2

h: hypotenuse

c1: leg 1

c2: leg 2

PS^2 = 2^2 + -2^2

PS = √ 4 + 4

PS = √8

PS = 2√2

S = (4 , 2)

R = (8 , 6)

SR = (8-4  ,  6-2)

SR = (4 , 4)

by pitagoras h ^ 2 = c1 ^ 2 + c2 ^ 2

h: hypotenuse

c1: leg 1

c2: leg 2

SR^2 = 4^2 + 4^2

SR = √ (16 + 16)

SR = √32

SR = 4√2

having the values ​​of 2 of its sides we multiply them and obtain their area

PS * RS = Area

2√2 * 4√2 =

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4 years ago
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