Answer:
<h2>There are 13 quarters, 5 nickels and 20 dimes.</h2>
Step-by-step explanation:
Givens
- Max has $5.50.
- He has eight more quarters than he does nickels.
- He had four times as many dimes as he has nickels.
From these statements, we can deduce algebraical expressions to solve the problem. Let's call
quarters,
nickels and
dimes.
(8 more quarters than nickels)
(he has four times as many dimes as he has nickels).
(Max has a total of $5.50, one quartes is $0.25, one nickel is $0.05 and one dime is $0.10).
Let's replace the first two expressions into the third equation
![0.25(n+8)+0.05n+0.10(4n)=5.50\\0.25n+2+0.05n+0.40n=5.50\\0.70n=5.50-2\\n=\frac{3.50}{0.70}\\ n=5](https://tex.z-dn.net/?f=0.25%28n%2B8%29%2B0.05n%2B0.10%284n%29%3D5.50%5C%5C0.25n%2B2%2B0.05n%2B0.40n%3D5.50%5C%5C0.70n%3D5.50-2%5C%5Cn%3D%5Cfrac%7B3.50%7D%7B0.70%7D%5C%5C%20n%3D5)
There are 5 nickels.
Now, we use this value to find the number of quarters
![q=5+8=13](https://tex.z-dn.net/?f=q%3D5%2B8%3D13)
There are 13 quarters.
Also, ![d=4(5)=20](https://tex.z-dn.net/?f=d%3D4%285%29%3D20)
There are 20 dimes.
Therefore, there are 13 quarters, 5 nickels and 20 dimes.
Hey there! :)
Answer:
SA = 144 cm².
Step-by-step explanation:
Find the surface area by calculating the areas of each of the lateral sides and bases:
In this instance, the bases are triangles, so the formula A = 1/2(bh) will be used:
Bases:
A = 1/2(bh)
A = 1/2(4·3)
A = 1/2(12)
A = 6 cm².
There are two bases, so:
6 × 2 = 12 cm²
Find the areas of the lateral sides using A = l × w:
5 × 11 = 55 cm²
4 × 11 = 44 cm²
3 × 11 = 33 cm²
Add up all of the areas:
12 + 55 + 44 + 33 = 144 cm².
Answer:
2 and 7/8
Step-by-step explanation:
3 + 3/8 - 1/2
3 + 3/8 - 4/8
3 - 1/8
2 and 7/8
Step-by-step explanation:
agile is the answer I'm pretty sure