Solve the system of equations.<br> 2x + 2y = -16<br> y = -x -8

Task 2 a. Do some research and find a city that has experienced population growth. Determine its population on January 1st of a

Galina-37 [17]

Exponential functions are functions defined by y = ab^x, where a represents the initial value, and b represents the rate

<h3>The equation of a city that has experienced a population growth</h3>

The initial population of the city is 10000, and the growth rate of the population is 4%.

So, the exponential equation is:

$y = 10000 * 1.04^x$

<h3>The equation of a city that has experienced a population decline</h3>

The initial population of the city is 12000, and the decay rate of the population is 3%.

So, the exponential equation is:

$y = 12000* 0.97^x$

<h3>The similarities in the equations</h3>

The similarity in both equations is that, they both represent exponential function.

<h3>The year the population of city A exceeds B</h3>

In (a) and (b), we have:

$y = 10000 * 1.04^x$ ---- city A

$y = 12000* 0.97^x$ --- city B

When city A exceeds city B, we have the following inequality

$10000 * 1.04^x > 12000 * 0.97^x$

Divide both sides by 10000

$1.04^x > 1.2 * 0.97^x$

Divide both sides by 0.97^x

$(\frac{1.04}{0.97})^x > 1.2$

$1.07^x > 1.2$

Take the natural logarithm of both sides

$\ln(1.07)^x > \ln(1.2)$

This gives

$x\ln(1.07) > \ln(1.2)$

Solve for x

$x > \frac{\ln(1.2)}{\ln(1.07)}$

$x > 2.69$

This means that, the population of city A will exceed city B after 3 years

<h3>The year the population of city A will be at least twice of city B</h3>

In (a) and (b), we have:

$y = 10000 * 1.04^x$ ---- city A

$y = 12000* 0.97^x$ --- city B

When city A is at least twice city B, we have the following inequality

$10000 * 1.04^x \ge 2 * 12000 * 0.97^x$

$10000 * 1.04^x \ge 24000 * 0.97^x$

Divide both sides by 10000

$1.04^x \ge 2.4 * 0.97^x$

Divide both sides by 0.97^x

$(\frac{1.04}{ 0.97})^x \ge 2.4$

$1.07^x \ge 2.4$

Take the natural logarithm of both sides

$\ln(1.07)^x \ge \ln(2.4)$

This gives

$x\ln(1.07) \ge \ln(2.4)$

Solve for x

$x\ge \frac{\ln(2.4)}{\ln(1.07) }$

$x\ge 12.9$

This means that, the population of city A will be at least twice city B after 13 years

Read more about exponential functions at:

brainly.com/question/11464095

3 0

3 years ago

I need some answer plssss help me

amid [387]

A. Find the unknown term of each proportion.

1. Answer: X=5

Step-by-step explanation:

x/7=15/21 ==> 21x=7(15) ==> 21x=105

21x/21=105/21 ==> x=5

2. Answer: X=40.5

Step-by-step explanation:

27/x=x/3 ==> 27(3)=x(x) ==> 81=2x

81/2=2x/2 ==> x=40.5

3. Answer: X=16

Step-by-step explanation:

8/x+2=4/9 ==> 8(9)=4(x+2) ==> 72=4x+8

72-8=4x+8-8 ==> 64=4x ==> 64/4=4x/4 ==> x=16

4. Answer: X=8

Step-by-step explanation:

3/x=30/80 ==> 3(80)=30x ==> 240=30x

240/30=30x/30 ==> x=8

5. Answer: M=56

Step-by-step explanation:

m/8=m+7/9 ==> 9m=8(m+7) ==> 9m=8m+56

9m-8m=8m-8m+56 ==> m=56

B. Solve the following.

1. Answer: 80 and 100

Step-by-step explanation:

4:5 ==> 4x+5x=180 ==> 9x=180

9x/9=180/9 ==> x=20

4(20)= 80 5(20)=100

2. Answer: 235.29

Step-by-step explanation:

3400/8 ==> 425

100,000/425= 235.29

7 0

3 years ago

A quadrilateral has exactly 3 congruent sides. Davis claims that the figure must be a rectangle. Why is his claim incorrect?

max2010maxim [7]

A rectangle has two pairs of congruent sides, but not 4 congruent sides.

3 0

3 years ago

Find the solution set of the inequality 7x−10≥16.

xenn [34]

×≥ 26/7 is the answer.

hope it helps!

5 0

4 years ago

Solve: −6x+4≤−16−2x . Express your answer in interval notation. (Express your answer in interval notation. Use U to indicate a u

FromTheMoon [43]

Answer:

[5, oo)

Step-by-step explanation:

Add 6x+16 to both sides:

20 ≤ 4x

5 ≤ x . . . . . . divide by 4

The solution interval is [5, oo).

6 0

3 years ago

Read 2 more answers

Solve the system of equations. 2x + 2y = -16 y = -x -8