We can simply multiply the roots together to find the original function.
(x + 2)(x - 4)(x - 4)(x - 3)
FOIL.
x^2 - 4x + 2x - 8(x - 4)(x - 3)
Combine like terms.
x^2 - 2x - 8(x - 4)(x - 3)
FOIL.
x^3 - 2x^2 - 8x - 4x^2 + 8x + 32(x - 3)
Combine like terms.
x^3 - 6x^2 + 32(x - 3)
FOIL.
x^4 - 6x^3 + 32x - 3x^3 + 18x^2 - 96
Combine like terms.
<h3>x^4 - 9x^3 + 18x^2 + 32x - 96 is the original function with the given roots.</h3>
Equation: 21+n=43.23
Process to find n
21+n=43.23
Subtract 21 from both sides
n=22.23
Using squares of integers numbers, it is found that the solution of the equation is located between the integers x = 1 and x = 2.
The equation given is:
The solution of the equation given is:
The squares of the integers numbers until the square root of 3 are:
Since 
, the square root of 3, which is the solution to the equation, is located between the integers x = 1 and x = 2.
A similar problem is given at brainly.com/question/3729492
The answer is y=x+1 hope this helpd
