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Genrish500 [490]
3 years ago
8

Solve for x using the diagram

Mathematics
1 answer:
liraira [26]3 years ago
6 0
Its bh 5 time 7 = 35 is ur hight 
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Answer:

THC

Step-by-step explanation:

7 0
3 years ago
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What is the volume of the prism given below?
KatRina [158]
Hi there!

Similar to the area of a triangle, it is 1/2 the area of a square. Therefore, we can multiply the base x height x length and divide it by 2 to find the volume of this figure.

WORK:
(6 x 8 x 19) / 2 = 456

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Questions 1-6 , need help ASAP , will award you brainiest
nika2105 [10]

Answer:

1. 13+10i

2. 28-(-4i)

3. -14-1i

4. 4 -i

5. 15+ 10i

6.8 - 5i^2

Step-by-step explanation:

8 0
3 years ago
If you help with the correct answer u are a god .pt2​
Brrunno [24]

a. Answer:  D: (∞, ∞)

                   R: (-∞, ∞)

<u>Step-by-step explanation:</u>

Theoretical domain is the domain of the equation (without an understanding of what the x-variable represents).

Theoretical range is the range of the equation given the domain.

c(p) = 25p

There are no restrictions on the p so the theoretical domain is All Real Numbers.

Multiplying 25 by All Real Numbers results in the range being All Real Numbers.

a) D: (∞, ∞)

   R: (-∞, ∞)

*********************************************************************************

b. Answer:  D: (0, 200)

                    R: (0, 5000)

<u>Step-by-step explanation:</u>

Practical domain is the domain of the equation WITH an understanding of what the x-variable represents.

Practical range is the range of the equation given the practical values of the domain.

The problem states that p represents the number of cups.  Since we can't have a negative amount of cups, p ≥ 0.  The problem also states that Bonnie will purchase a maximum of 200 cups. So, 0 ≤ p ≤ 200

The range is 25p →  (25)0 ≤ (25)p ≤ (25)200

                             →      0   ≤  25p  ≤  5000

b) D: (0, 200)

   R: (0, 5000)

5 0
3 years ago
If AB = 12 and CB = 10, then the height of the triangle is:
Ierofanga [76]
AD = DB = AB/2 = 6
cd = \sqrt{{bc}^{2} - {db}^{2} } \\ cd = \sqrt{64} \\ cd = 8
3 0
3 years ago
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