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3 years ago

Use the slope formula to find the slope between the given two points. (2, 1) and (8, 9)

Mathematics

1 answer:

Elanso [62]3 years ago

5 0

Answer:

slope = -1

Step-by-step explanation:

slope formula: (y2-y1)/(x2-x1)

(1-2) divided by (9-8) = -1/1 = -1

slope = -1

you can switch it up by doing (9-8) divided by (1-2), but it won't make a difference I think.

You might be interested in

Find f (25/29) if f (x)=-5x+5

devlian [24]

Answer:

f(25/29) = $\frac{20}{29}$

Step-by-step explanation:

In order to do this problem, we need to plug in $\frac{25}{29}$ for x. When we plug it in we get $f(x) = -5(\frac{25}{29}) + 5$ . After this we can start by multiplying. When we multiply $-5(\frac{25}{29} )$ we get $(\frac{-125}{29}) + 5$ . Since the fraction cannot be simplified any further, we can now add 5. In order to add 5 we need to find a common denominator, which in this case will be 29. Changing the denominator to 29 gives us $(\frac{-125}{29}) + \frac{145}{29}$ because when changing the denominator we have to multiply the numerator by the same number. After adding these fractions we get our answer of $\frac{20}{29}$ .

5 0

2 years ago

Find each equivalent fraction

boyakko [2]

Here the answers I hope this helps!

8 0

3 years ago

Read 2 more answers

Seth runs every day. He jogs 6 mies odos

hoa [83]

Answer:

Step-by-step explanation:

Assuming he jogs 6 miles a day (Monday to Saturday?)

6 miles * 6 days = 36 miles

Sunday = 5 miles

In one week he runs a total of 41 miles

$36 + 5 = 41$ miles

In 3 weeks he runs a total of 123 miles

$41 * 3 = 123$ miles

8 0

3 years ago

Which trigonometric ratios are correct for triangle ABC? Check all that apply

sergij07 [2.7K]

Consider an angle M with measure m≠90°, in a right triangle.

Let

OPP denote the length of the side opposite to M,
ADJ denote the length of the side adjacent to M, and
HYP denote the hypotenuse.

then:

Sin(M) = OPP/HYP
Cos(M)= ADJ/HYPP
Tan(M)=OPP/ADJ

Back to our problem,

using the Pythagorean we can find the length of AB:

$|AB|^2+|AC|^2=|BC|^2\\\\|AB|^2+9^2=18^2\\\\|AB|^2=18^2-9^2\\\\|AB|^2=(18-9)(18+9)=9 \cdot 27=9 \cdot 9 \cdot3\\\\|AB|=9 \sqrt{3} 
$

$Sin(C)= \frac{OPP}{HYP}=\frac{9 \sqrt{3} }{18}= \frac{ \sqrt{3} }{2}$
$Cos(B)= \frac{ADJ}{HYP}= \frac{9 \sqrt{3}}{18}= \frac{ \sqrt{3}}{2}$
$Tan(C)= \frac{OPP}{ADJ}= \frac{9 \sqrt{3} }{9}= \sqrt{3}$
$Sin(B)= \frac{OPP}{HYP}= \frac{9}{18}= \frac{1}{2}$
$Tan(B)= \frac{OPP}{ADJ}= \frac{9}{9 \sqrt{3}}= \frac{1}{ \sqrt{3} }= \frac{ \sqrt{3}}{3}$

Answer: 1, 3, 4

5 0

3 years ago

Suppose that the weights of the basketball players of a tournament are approximately normally distributed with a mean of 190lb a

Olegator [25]

Answer:

b. 2.5%

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

$\mu = 190, \sigma = 15$

Which of the following is a good approximation of the probability that a randomly selected player weighs more than 220lb?

This is 1 subtracted by the pvalue of Z when X = 220. So

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{220 - 190}{15}$

$Z = 2$

$Z = 2$ has a pvalue of 0.9772

1 - 0.9772 = 0.0228

Close to 2.5%

So the correct answer is:

b. 2.5%

4 0

3 years ago