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Elis [28]
3 years ago
14

Please help me solve. x-(-16)=44 i know the answer i just need the work

Mathematics
1 answer:
Marat540 [252]3 years ago
6 0

x+16=44

x=44-16

x=28

That is the answer

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LCM of 189024 <br>please give me answer my question​
ololo11 [35]

Answer:

360

Step-by-step explanation:

We need to find the LCM of 18,90 and 24.

The prime factorization of 18 = 2 × 3 × 3

The prime factorization of 90 = 2 × 5×3×3

The prime factorization of 24 = 2 × 3×2×2

LCM is least common multiple.

LCM = 2 x 2 x 2 x 3 x 3 x 5

= 360

Hence, the LCM of 18,90 and 24 is 360.

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2 years ago
In an A-frame house, the two congruent sides each form a 76° angle with the ground. What is the angle formed at the peak by the
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3 years ago
The weight of people in a small town in Missouri is known to be normally distributed with a mean of 186 pounds and a standard de
OleMash [197]

Answer:

the probability that a random sample of 17 persons will exceed the weight limit of 3,417 pounds is 0.0166

Step-by-step explanation:

The summary of the given statistical data set are:

Sample Mean = 186

Standard deviation = 29

Maximum capacity 3,417 pounds or 17 persons.

sample size = 17

population mean =3417

The objective is to determine the probability  that a random sample of 17 persons will exceed the weight limit of 3,417 pounds

In order to do that;

Let assume X to be the random variable that follows the normal distribution;

where;

Mean \mu = 186 × 17 = 3162

Standard deviation = 29* \sqrt{17}

Standard deviation = 119.57

P(X>3417) = P(\dfrac{X - \mu}{\sigma}>\dfrac{X - \mu}{\sigma})

P(X>3417) = P(\dfrac{3417 - \mu}{\sigma}>\dfrac{3417 - 3162}{119.57})

P(X>3417) = P(Z>\dfrac{255}{119.57})

P(X>3417) = P(Z>2.133)

P(X>3417) =1- 0.9834

P(X>3417) =0.0166

Therefore; the probability that a random sample of 17 persons will exceed the weight limit of 3,417 pounds is 0.0166

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3 years ago
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Salsk061 [2.6K]

Answer:

You are right

Step-by-step explanation:

So basically find the absolute maximum of the graph that the function creates, the highest peak is the spot with the greatest y-value, in this case is (60, 1600).

The x-value that creates the greatest y is also the x-value of the vertex for that function of yours (since your function has end behavior of both ends down). To find the x-value of the vertex, get the average of the 2 x-intercepts. So (20+100)/2, which is 60.

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3 years ago
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