All categories

3 years ago

Lines AC and BD intersect at O as shown. What is the measure of

Mathematics

1 answer:

UkoKoshka [18]3 years ago

5 0

Answer:

X=4

Step-by-step explanation:

25x + 25x = 50

20 + 20 = 40

50 + 40 = 90

90x = 360

X = 4

You might be interested in

Find a. Round to the nearest tenth:

Ulleksa [173]

Step-by-step explanation:

In the following triangle, a= ? , b= 2cm.

m<B= 105° , m<C = 15° ,m< A =?

Now, we know that sum of the interior angles of the triangle = 180°

m<B+m<C +m< A =180°

105°+15°+m< A=180°

m< A= 180- 120° = 60°

$\frac{ \sin( A) }{a} = \frac{ \sin(B) }{b}$

$\frac{ \sin(60) }{a} = \frac{ \sin(105) }{2}$

$a = \frac{ \sin(60) }{ \sin(105) } \times 2$

$a = 1.79$

$a = 1.8$

6 0

3 years ago

What so the lines in this equation mean? | x - y |

dlinn [17]

absolute value- absolute value is the distance away from zero it cannot be negative

5 0

3 years ago

Read 2 more answers

A number cube is rolled three times. An outcome is represented by a string of the sort OEE (meaning an odd number on the first r

Kryger [21]

The probability of occurrence for the events A, B and C is; 1/4.

<h3>What is the probability of occurrence of.the described events?</h3>

For the first event A in which case, there's no odd number on the first two rolls, the possible events are; EEE and EEO. Consequently, the required probability is;

Event A = 2/8 = 1/4.

For the event B in which case, there's an even number on both the first and last rolls; the possible events are; EEE and EOE. Consequently, the required probability is;

Event B = 2/8 = 1/4.

For the event C in which case, there's an odd number on each of the first two rolls; the possible events are; OOO and OOE. Consequently, the required probability is;

Event C = 2/8 = 1/4.

Read more on probability;

brainly.com/question/251701

#SPJ1

7 0

2 years ago

PLEASE HELP ITS DUE TODAY THANKS!

Nutka1998 [239]

I got 130.24 square feet. Hope that helps.

8 0

3 years ago

Read 2 more answers

A large corporation starts at time t = 0 to invest part of its receipts continuously at a rate of P dollars per year in a fund f

Andrews [41]

Answer:

$A = \frac{P}{r}\left( e^{rt} -1 \right)$

Step-by-step explanation:

This is <em>a separable differential equation</em>. Rearranging terms in the equation gives

$\frac{dA}{rA+P} = dt$

Integration on both sides gives

$\int \frac{dA}{rA+P} = \int dt$

where $c$ is a constant of integration.

The steps for solving the integral on the right hand side are presented below.

$\int \frac{dA}{rA+P} = \begin{vmatrix} rA+P = m \implies rdA = dm\end{vmatrix} \\\\\phantom{\int \frac{dA}{rA+P} } = \int \frac{1}{m} \frac{1}{r} \, dm \\\\\phantom{\int \frac{dA}{rA+P} } = \frac{1}{r} \int \frac{1}{m} \, dm\\\\\phantom{\int \frac{dA}{rA+P} } = \frac{1}{r} \ln |m| + c \\\\&\phantom{\int \frac{dA}{rA+P} } = \frac{1}{r} \ln |rA+P| +c$