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3 years ago

PLEASE PLEASE HELP ME !!!i need to solve this doing the zero product property

Mathematics

1 answer:

Dafna11 [192]3 years ago

6 0

Factor the trinomial and you would get (x-7)(x+5)=0 and then you get
x=7 and x=-5

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Find the value of 100-98+96-94+92-90+...+8-6+4-2

Pachacha [2.7K]

Answer:

solution

100-98 =2

96-94 = 2

92-90 = 2

8-6 = 2

4-2 =2

2+2+2+2+2=10✓

8 0

3 years ago

In order to play in the bounce house at the party, children must weigh within 8 pounds of the 34

larisa [96]

Answer:

a) 8 pounds.

b) [26,42]

c) $26 \leq w \leq 42$

d) Weight above 42 pounds, so she cannot.

Step-by-step explanation:

a. What is the margin of error?

Within 8 pounds, so margin of error of 8 pounds.

b. Express the acceptable weights as an interval.

34 - 8 = 26

34 + 8 = 42

[26,42]

c. Write an expression in the format to represent the interval.

$26 \leq w \leq 42$

d. Sally weighs 44 pounds. Can she play in the bounce house?

Weight above 42 pounds, so she cannot.

8 0

3 years ago

Classify the polygon by its number of sides. State whether the polygon appears to be regular or not regular it’s has 8 sides

Alex73 [517]

Answer:

octagon, regular

Step-by-step explanation:

it has eight sides and the side all measure the same amount

7 0

3 years ago

When converting 16/3 from improper to a mixed number, what will the whole number be? first one will get mark brainlist

N76 [4]

Answer: 5 1/3

Step-by-step explanation:

3 0

3 years ago

Q5: Identify the graph of the equation and write an equation of the translated or rotated graph in general form.

MAVERICK [17]

Answer:

$d.\:ellipse;\:3x^2+y^2+6x-6y+3=0$ .

Step-by-step explanation:

The given conic has equation;

$3x^2+y^2=9$

Divide through by 9.

$\Rightarrow \frac{3x^2}{9}+\frac{y^2}{9}=\frac{9}{9}$

$\Rightarrow \frac{x^2}{3}+\frac{y^2}{9}=1$ .

This is an ellipse centered at the origin;

This ellipse has been translated so that the center is now at;

$(-1,3)$

The translated ellipse has equation;

$\frac{(x+1)^2}{3}+\frac{(y-3)^2}{9}=1$ .

Clear the fraction;

$3(x+1)^2+(y-3)^2=9$ .

Expand;

$3(x^2+2x+1)+(y^2-6y+9)=9$ .

$3x^2+6x+3+y^2-6y+9=9$ .

Write in general form;

$3x^2+y^2+6x-6y+9-9+3=0$ .

$3x^2+y^2+6x-6y+3=0$ .

The correct choice is D

4 0

3 years ago

Read 2 more answers