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3 years ago

Which expression has a value of 35 when p = 7

Mathematics

1 answer:

GREYUIT [131]3 years ago

8 0

Answer:

There are a lot of expressions but here's an example:

p+28 = 35

5p = 35

Step-by-step explanation:

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There is no X intercept.
The Y intercept is (0,10)

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Using the pythagorean theorem, calculate the length of the missing sides (c1, c2, c3)

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Answer:

the Pythagorean theorem states: a^2 + b^2 = c^2

1) in this case a=18 and b1=25

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now you can use the same technique as in the first case, and the final answer will be cca. 23.4 = c2

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3 years ago

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notsponge [240]

<h2>Question:-</h2>

If a = 6 - $\sqrt{35}$ , find the value of a² + $\frac{1}{a²}$

<h2>Solution:-</h2>

a = 6 - $\sqrt{35}$ (Given)

Now, first of all we have to find the value of $\frac{1}{a}$ .

So, $\frac{1}{a}$ = $\frac{1}{6 \: - \: \sqrt{35}}$

$\frac{1}{a}$ = $\frac{6 \: + \sqrt{35}}{(6 \: - \: \sqrt{35})(6 \: + \: \sqrt{35})}$

$\frac{1}{a}$ = $\frac{6 \: + \sqrt{35}}{(6)² \: - \: (\sqrt{35})²}$

$\frac{1}{a}$ = $\frac{6 \: + \sqrt{35}}{36 \: - \: 35}$ $(\because \sqrt{35} \: × \: \sqrt{35} \: = \: 35)$

$\frac{1}{a}$ = $\frac{6 \: + \: \sqrt{35}}{1}$

$\frac{1}{a}$ = 6 + $\sqrt{35}$

Now, we have to find the value of a² + $\frac{1}{a²}$

So, a² + $\frac{1}{a²}$ = $(a \: + \frac{1}{a})²$ - 2.a. $\frac{1}{a}$

a² + $\frac{1}{a²}$ = $(6 \: - \sqrt{35} \: + \: 6 \: + \sqrt{35})²$ - 2

a² + $\frac{1}{a²}$ = (12)² - 2

a² + $\frac{1}{a²}$ = 144 - 2

a² + $\frac{1}{a²}$ = 142

The value of a² + $\frac{1}{a²}$ is 142. [Answer]

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