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Eddi Din [679]
4 years ago
10

find 44% of 8.79. user: find 8% of 2.36. user: darren teaches a class of 25 students. he assigns homework 3 times a week, and ea

ch assignment consists of 12 problems. how many problems must darren correct each week?
Mathematics
1 answer:
Andrews [41]4 years ago
7 0
44% of 8.79 = 
0.44 (8.79) = 3.87 (thats rounded) 

8% of 2.36 =
0.08 (2.36) = 0.19 (rounded)

25 students, homework 3 times per week, 12 problems each assignment 
3(12) = 36 problems per student...36(25) = 900 problems for 25 students.
ur answer is 900

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Hoochie [10]
Your answer is 3 lb.
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3 years ago
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Rich is comparing the cost of maintaing his car with the depreciating value of the car. When will the cost and value be the same
goldfiish [28.3K]

Complete question:

Rich is comparing the cost of maintaining his car with the depreciation value of the car.

The value starts at $20,000 and decreases by 15% each year. The maintanance cost is $500 the first year and increases by 28% per year.

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Answer:

9 years

Step-by-step explanation:

Depreciation is modeled by an exponential function :

A = p(1 - r)^t [decrease, '-']

A = 20,000(1 - 0.15)^t

A = 20000(0.85)^t - - - (1)

Maintainace cost :

A = p(1 + r)^t ; [increase, '+']

A = 500(1 + 0.28)^t

A = 500(1.28)^t - - - (2)

Equating (1) and 2

20000(0.85)^t = 500(1.28)^t

1.28^t / 0.85^t = 20000/500

(1.28 / 0.85)^t = 40

Take log of both sides

Log (1.28 / 0.85)^t = log 40

t * 0.1777910 = 1.6020599

t = 1.6020599 / 0.1777910

t = 9.01

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8 0
3 years ago
If the diameter of a youth baseball is 2. 8 inches and the diameter of an adult softball is 3. 8 inches, what is the approximate
Molodets [167]

The approximate difference in their volumes is 17.2 cubic inches

<h3>How to determine the difference in the volume?</h3>

The given parameters are:

Diameter, d = 2.8

Diameter, D = 3.8

The radii are the half of the diameter.

So, we have:

r = 1.4

R = 1.9

The volume of the balls is then calculated using:

V = \frac{4}{3}\pi r^3

The difference is then represented as:

D = \frac{4}{3}\pi (R^3 - r^3)

Substitute known values

D = \frac{4}{3}* 3.14* (1.9^3 - 1.4^3)

Evaluate

D = 17.2

Hence, the approximate difference in their volumes is 17.2 cubic inches

Read more about volumes at:

brainly.com/question/1972490

#SPJ1

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