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PtichkaEL [24]
2 years ago
10

Two mechanics worked on a car. The first mechanic worked for 15 hours, and the second mechanic worked for 5 hours. Together they

charged a total of $1800 . What was the rate charged per hour by each mechanic if the sum of the two rates was $150 per hour?
Mathematics
1 answer:
GrogVix [38]2 years ago
7 0
You have to make a equation like 15m+5m=1800 and substitute m for 150 (m for dollars per hour. or whatever letter you want) and solve from there

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Mr. Malone is contemplating which chauffeured car service to take to the airport. The first costs $28 upfront and $2 per mile. T
Ksju [112]

Answer:

The distance is 8 miles.

Step-by-step explanation:

First, we need to write an equation for each of chauffeured car services.

The first one = 28 + 2x = ?

The second one = 13 + 5x = ?

Next, we need to figure out what x is. Usually I just plug in random numbers, but I'm sure there's a better way to do it.

I first plugged in 2 as x.

28 + 4 = 32

13 + 10 = 23

That didn't work, so I then plugged in 5.

28 + 10 = 38

13 + 25 = 38

So 5 would be the correct answer for what is the distance.

8 0
2 years ago
Seventy percent of all vehicles examined at a certain emissions inspection station pass the inspection. Assuming that successive
NeX [460]

Answer:

(a) 0.343

(b) 0.657

(c) 0.189

(d) 0.216

(e) 0.353

Step-by-step explanation:

Let P(a vehicle passing the test) = p

                        p = \frac{70}{100} = 0.7  

Let P(a vehicle not passing the test) = q

                         q = 1 - p

                         q = 1 - 0.7 = 0.3

(a) P(all of the next three vehicles inspected pass) = P(ppp)

                           = 0.7 × 0.7 × 0.7

                           = 0.343

(b) P(at least one of the next three inspected fails) = P(qpp or qqp or pqp or pqq or ppq or qpq or qqq)

      = (0.3 × 0.7 × 0.7) + (0.3 × 0.3 × 0.7) + (0.7 × 0.3 × 0.7) + (0.7 × 0.3 × 0.3) + (0.7 × 0.7 × 0.3) + (0.3 × 0.7 × 0.3) + (0.3 × 0.3 × 0.3)

      = 0.147 + 0.063 + 0.147 + 0.063 + 0.147 + 0.063 + 0.027

      = 0.657

(c) P(exactly one of the next three inspected passes) = P(pqq or qpq or qqp)

                 =  (0.7 × 0.3 × 0.3) + (0.3 × 0.7 × 0.3) + (0.3 × 0.3 × 0.7)

                 = 0.063 + 0.063 + 0.063

                 = 0.189

(d) P(at most one of the next three vehicles inspected passes) = P(pqq or qpq or qqp or qqq)

                 =  (0.7 × 0.3 × 0.3) + (0.3 × 0.7 × 0.3) + (0.3 × 0.3 × 0.7) + (0.3 × 0.3 × 0.3)

                 = 0.063 + 0.063 + 0.063 + 0.027

                 = 0.216

(e) Given that at least one of the next 3 vehicles passes inspection, what is the probability that all 3 pass (a conditional probability)?

P(at least one of the next three vehicles inspected passes) = P(ppp or ppq or pqp or qpp or pqq or qpq or qqp)

=  (0.7 × 0.7 × 0.7) + (0.7 × 0.7 × 0.3) + (0.7 × 0.3 × 0.7) + (0.3 × 0.7 × 0.7) + (0.7 × 0.3 × 0.3) + (0.3 × 0.7 × 0.3) + (0.3 × 0.3 × 0.7)

= 0.343 + 0.147 + 0.147 + 0.147 + 0.063 + 0.063 + 0.063

                  = 0.973  

With the condition that at least one of the next 3 vehicles passes inspection, the probability that all 3 pass is,

                         = \frac{P(all\ of\ the\ next\ three\ vehicles\ inspected\ pass)}{P(at\ least\ one\ of\ the\ next\ three\ vehicles\ inspected\ passes)}

                         = \frac{0.343}{0.973}

                         = 0.353

3 0
3 years ago
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soldi70 [24.7K]

Answer:

A

Step-by-step explanation:

I feel strongly that it is A.

5 0
2 years ago
Which number should.be added to the data so that the range of the data is 31? 54,72,64,57
Sergio039 [100]

Answer:  41 or 85

<u>Step-by-step explanation:</u>

Range is the difference between the largest number and the smallest number.

The largest number is 72.  72 - 31 = 41

The smallest number is 54.  54 + 31 = 85

Adding either ONE of those numbers will result in a range of 31.

3 0
3 years ago
EOC algebra. 
Fofino [41]
The equation that would represent the new area N of the floor of the cage would be 
N=w2+4w which would be a 
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