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kozerog [31]
3 years ago
15

Someone help plz I need help

Mathematics
1 answer:
Firlakuza [10]3 years ago
4 0

Answer:

-3 i think because it is low i am soooo sorry if its wrong i really wasnt trying to get points i wanted to help hope for the best

Step-by-step explanation:

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The graph of a linear function intersects with the x axis at a point with an abscissa of 4 and with the y axis at a point with a
goldenfox [79]
We know that

points are
x intercept
A (4,0)

y intercept
B (0,11)

step 1
find the equation of a line
m=(y2-y1)/(x2-x1)--------> m=(11-0)/(0-4)------> m=-11/4

with m and the point B (0,11)
y-y1=m*(x-x1)y-11=(-11/4)*(x-0)---------> y=-(11/4)x+11

the answer is 
the formula of the function is y=-(11/4)x+11

see the attached figure

7 0
3 years ago
victor want to make a book tower of height 48 cm .If the thickness of book is 12 mm ,how many books will he need to make the des
lions [1.4K]

Answer:

40

Step-by-step explanation:

1. Change 48 cm to mm, which will give you 480 mm

2. Divide 480 mm by 12 mm, that will give you 40

Therefore, Victor needs 40 books to make his desired height.

6 0
3 years ago
The number 15, 56 rounded to the nearest thousand is 15,000. Which numbers could be the missing digit?
Virty [35]

The numbers 0, 1, 2, 3, 4 could all be the missing digit because they're all numbers that round down. hope this helped!

4 0
4 years ago
Read 2 more answers
2. If a person is walking at a pace of 2/3 mile every 2/5 hour, how long would it take
viva [34]
It would take them a half and hour
3 0
3 years ago
You have 42,784 grams of a radioactive kind of curium. If its half-life is 18 years, how much will be left after 72 years?
s344n2d4d5 [400]

Answer:

2,674.14 g

Step-by-step explanation:

Recall that the formula for radioactive decay is

N = N₀ e^(-λt)

where,

N is the amount left at time t

N₀ is the initial amount when t=0, (given as 42,784 g)

λ = coefficient of radioactive decay

  = 0.693 ÷ Half Life

  = 0.693 ÷ 18

  = 0.0385

t = time elapsed (given as 72 years)

e = exponential constant ( approx 2.7183)

If we substitute these into our equation:

N = N₀ e^(-λt)

= (42,787) (2.7183)^[(-0.0385)(72)]

= (42,787) (2.7183)^(-2.7726)

=  (42,787) (0.0625)

= 2,674.14 g

6 0
3 years ago
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