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ddd [48]
3 years ago
11

Can someone help me with the question in the image?

Mathematics
1 answer:
soldier1979 [14.2K]3 years ago
3 0

Step-by-step explanation:

m< I = m < 2 = m < 3

7y+16 = 2X

7y - 2x +16 = O ............I

7y +16 = 4X _30

7y -4 x + 46 = 0 ...............2

solve eq I,2

2 X - 30= o

X= 15

substitute in I

7X= 14

y = 2

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Which expression is NOT equivalent to 24?<br><br> 2x2x2x3<br> 2x2x6<br> 2x2x3x3<br> 2x4x3
professor190 [17]

Answer:

2x2x3x3=36...so it is not equivalent to 24

5 0
3 years ago
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Each week, mr. jones goes to the grocery store. mr.jones estimates that he will spend $120 when he goes to the grocery store thi
Aliun [14]
Estimated amount that Mr. Jones thought would be spending each week for grocery = $120
Amount actually spent by Mr.Jones in the grocery store = $94
Error in calculation of the amount of spending = (120 - 94) dollars
                                                                           = $26
Percentage error in calculation = (26/120) * 100
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                                                   = 130/6
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So there is 21.67% error in the calculation of Mr. Jones. I hope you got the answer you were looking for.

8 0
3 years ago
I need help please???
Solnce55 [7]

Answer:

A(-5,-1) B(-1,1) C(3,4) D(2,-4) E(0,-6)

Step-by-step explanation:

(x,y)

x being the horizontal line (going across)

y being the vertical line (up and down)

6 0
3 years ago
There are seven black marbles and nine white marbles in a bag what is the aprroximate probability of drawing two black marbles a
iren2701 [21]
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Hope this works
5 0
3 years ago
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WILL MARK B!<br> Please I need help I have a quiz
MArishka [77]

Answer:

a) 2x² - x + 3 = x(2x + 1) - 2x

<=> 2x² - x + 3 = 2x² + x - 2x

<=> 3 - x = - x

<=> 3 = 0

=> no solution

b) x/2 - x/3 - x/4 = 1/12

\frac{6x}{12}  -  \frac{4x}{12}  -  \frac{3x}{12}  =  \frac{1}{12}  \\  \\  \frac{ - x}{12}  =  \frac{1}{12}  \\  \\  =  >  - x = 1 \\  \\  \\  <  =  > x = 1

=> the euqation has the solution x = 1

c) |x - 5| = 2|x|

=> x - 5 = 2x

or x - 5 = -2x

<=> x = -5

or 3x = 5

<=> x = -5

x = -5or x = 5/3

d) defined conditions: 2 - x 》 0

<=> x 《 2

we have:

\sqrt{x + 4}  = 2 - x \\  <  =  > x + 4 = (2 - x) {}^{2}   \\  <  =  > x + 4 =  {x}^{2}  - 4x + 4 \\  <  =  >  {x}^{2}  - 5x = 0 \\  <  =  > x(x - 5) = 0 \\

<=> x = 0 (because x 《 2)

e)

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<=> x = -1/4

3 0
3 years ago
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