2009 - 1894 = 115
That appears to be the same number as
the one that appears in Choice-'B'.
2. f(x) = x - 2x² - 5 + 10x
=-2x² + 8x - 5
f'(x)= -4x + 8
4. y = 100(45x - 30 - 3x³ + 2x²)
= 100(-3x³ + 2x² + 45x -30)
= -300x³ + 200x² + 4500x - 3000
y' = -900x² + 400x + 4500
Answer:
7.065
Step-by-step explanation:
Answer:
12.
Step-by-step explanation:
Replace k in the radical by -2:
So we have √(-72*-2)
= √144
= 12.
The first step is to calculate what fraction of the counters that Rob has.
Add all the portions together to find the total: 5+6+7= 18
Rob has 5 out of the 18, or 5/18, or 0.278
Next, do the same for the end ratio:
7+9+8= 24 and Rob has 7/24, or 0.292
By comparing his beginning portion (0.278) to his end portion (0.292) it is clear that he has a greater portion of the total counters. Given that the problem states that the number of counters stays the same, Rob must have more counters than he started with.
