A digit is a number in one of the places, so for example the number 54 has two digits; a tens place digit (5) and a ones place digit (4).
Say the mystery number is a two digit number = xy
* that's not x times y but two side by side digits.
Info given:
<span>the sum of the digits of a two-digit number is 6
x + y = 6 </span>
<span>if the digits are reversed, yx the difference between the new number and the original number is 18.
**To obtain the number from digits you must multiply by the place and add the digits up. (Example: 54 = 10(5) + 1(4))
Original number = 10x + y
Reversed/New number = 10y + x
Difference:
10y + x - (10x + y) = 18
9y - 9x = 18
9(y - x) = 18
y - x = 18/9
y - x = 2
Now we have two equations in two variables
</span>y - x = 2
<span>x + y = 6
Re-write one in terms of one variable for substitution.
y = 2 + x
sub in to the other equation to combine them.
x + (2 + x) = 6
2x + 2 = 6
2x = 6 - 2
2x = 4
x = 2
That's the tens digit for the original number. Plug this value into either of the equations to obtain y, the ones digit.
2 + y = 6
y = 4
number "xy" = 24
</span>
The answer is 52+7x I hope this helps
The answer I came up with was ×^6-4. Just rewrite it. I hope this was helpful.
Answer:
x = 4
Step-by-step explanation:
Answer:
=26x^3−12x^2+5x+7
Step-by-step explanation:
2x^3−3x+11−(3x^2+1)(4−8x)
Distribute:
=2x^3+−3x+11+24x^3+−12x^2+8x+−4
Combine Like Terms:
=2x^3+−3x+11+24x^3+−12x2+8x+−4
=(2x^3+24x^3)+(−12x^2)+(−3x+8x)+(11+−4)
=26x^3+−12x^2+5x+7
