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UkoKoshka [18]
1 year ago
6

Given a graph for the transformation of f(x) in the format g(x) = f(x) + k, determine the k value.

Mathematics
1 answer:
dimaraw [331]1 year ago
5 0

Answer:

4

Step-by-step explanation:

g(x) is the graph of f(x) shifted up 4 units.

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8x4=$32
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4 years ago
Borrow 1 from the whole number to rewrite 8 10/24.
koban [17]

Answer:

A. 7\frac{34}{24}

Step-by-step explanation:

We are given  the expression, 8\frac{10}{24}

On re-writing the expression after borrowing 1, we have,

8\frac{10}{24} = 7(\frac{10}{24}+1)

i.e. 8\frac{10}{24} = 7(\frac{10}{24}+\frac{24}{24})

i.e. 8\frac{10}{24} = 7\frac{34}{24}

Thus, the equivalent expression after borrowing 1 from the given expression is 7\frac{34}{24}.

Hence, option A is correct.

4 0
3 years ago
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Suppose that prior to conducting a coin-flipping experiment, we suspect that the coin is fair. How many times would we have to f
BabaBlast [244]

Answer:

153 times

Step-by-step explanation:

We have to flip the coin in order to obtain a 95.8% confidence interval of width of at most .14

Width = 0.14

ME = \frac{width}{2}

ME = \frac{0.14}{2}

ME = 0.07

ME\geq z \times \sqrt{\frac{\widecap{p}(1-\widecap{p})}{n}}

use p = 0.5

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0.07 \geq 1.727 \times \sqrt{\frac{0.5(1-0.5)}{n}}

\frac{0.07}{1.727}\geq sqrt{\frac{0.5(1-0.5)}{n}}

(\frac{0.07}{1.727})^2 \geq \frac{0.5(1-0.5)}{n}

n \geq \frac{0.5(1-0.5)}{(\frac{0.07}{1.727})^2}

n \geq 152.169

So, Option B is true

Hence  we have to flip 153 times the coin in order to obtain a 95.8% confidence interval of width of at most .14 for the probability of flipping a head

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3 years ago
Find the unit rate in each situation below in miles per hour.
sveticcg [70]
B. Is the correct answer
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Help please!!! Solve 49^ x = 7
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The variable <em>x </em>is equal to 0.5

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