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fomenos
3 years ago
8

Rectangle A′B′C′D′ is the image of rectangle ABCD after a dilation. What is the scale factor of the dilation? Enter your answer

in the box. $\text{Basic}$ $x$$y$$x^2$$\sqrt{ }$$\frac{x}{ }$ $x\frac{ }{ }$ $x^{ }$$x_{ }$$\degree$$\left(\right)$$\abs{ }$$\pi$$\infty$ A coordinate plane that includes two rectangles rectangle ABCD and rectangle A prime B prime C prime D prime. For rectangle ABCD, point A is at (-5, -2), point B is at (-8, -2), point C is at (-8, -5), and point D is at (-5, -5). For rectangle A prime B prime C prime D prime, point A prime is at (-2.5, -1), point B prime is at (-4, -1), point C prime is at (-4, -2.5), and point D prime is at (-2.5, -2.5).
Mathematics
2 answers:
CaHeK987 [17]3 years ago
8 0

Answer:

1/2

Step-by-step explanation:

just took test hope it helps! :)

dybincka [34]3 years ago
5 0

Answer:

1/2

Step-by-step explanation:

You might be interested in
-11 2/3* (-4 1/5)<br> A) -44 2/15<br> B)44 2/15<br> C)49 <br> D)-49
Kryger [21]

\text {Hey! Let's Solve this Equation!}

\text {We Know That:}

\text {Multiplying a Negative to a Negative will Equal a Positive.}

\text {Multiply:}

\text {-11*-4=44}\\\text {2*1=2}\\\text {3*5=15}

\text {Your Answer would be:}

\fbox{4 2/15}

\text {Best of Luck!}

4 0
4 years ago
What is the area of the top surface of a circular manhole cover that has a radius of 30cm
EastWind [94]
900pi or 2826 (if multiplying by 3.14)
A = r^2*pi
8 0
3 years ago
Algebra is very hard espc without teacher help - solve for x
ehidna [41]

Answer:

In explanation

Step-by-step explanation:

First, we simplify the parentheses:

(12x+16)-7x=(10x-20)+6

Simplify:

5x+16=10x-14

Isolate x:

30=5x

Divide 5 by both sides

x=6

<em>Hope this helped! Have a good day.</em>

4 0
3 years ago
You are anchoring your boat. the water is 20 feet deep. how much anchor line should you use
scoray [572]

Answer: The answer is 100 to 140 feet.


Step-by-step explanation: Given that we are anchoring our boat and the water is 20 feet deep. We are to calculate the anchor line we should use.

General rule of calculating anchor line is given by

Multiplying the depth of the water by 5 to 7 . For example, if the water depth is 'x' feet, then we will multiply 'x' feet by 5 to 7 to get the amount of anchor line to put out.

Here, the depth of water = 20 feet.

So, the anchor line should be 5 × 20 to 7 × 20 feet, i.e., 100 to 140 feet.

Thus, the anchor line should be 100 to 140 feet.


4 0
3 years ago
Read 2 more answers
1. Given GH = 7x + 3, HI= 3x - 5,<br> and GI= 9x + 5.<br> H<br> G<br> A. Find x:<br> B. Find GH:
blsea [12.9K]

Answer:

\boxed{\bf x=7}

\boxed{\bf GH= 52}

Step-by-step explanation:

In the line segment..

\bf 7x+3+3x-5=9x+5

Combine like terms.

  • \bf 10x-2=9x+5

Add -2 to both sides.

  • \bf 10x-2+2=9x+5+2
  • \bf 10x=9x+7

Subtract 9x from both sides.

  • \bf 10x-9x=9x+7-9x
  • \boxed{\bf x=7}

\bf GH=7x+3

  • \bf 7(7)+3
  • \bf 49+3
  • \boxed{\bf 52}
<h3>__________________</h3>
6 0
3 years ago
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