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2 years ago

Algebra is very hard espc without teacher help - solve for x

Mathematics

1 answer:

ehidna [41]2 years ago

4 0

Answer:

In explanation

Step-by-step explanation:

First, we simplify the parentheses:

$(12x+16)-7x=(10x-20)+6$

Simplify:

$5x+16=10x-14$

Isolate x:

$30=5x$

Divide 5 by both sides

$x=6$

Hope this helped! Have a good day.

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Another submarine descent can be represented as y= -240 x where y is the elevation and x is time in hours. How long will it take

Juli2301 [7.4K]

Answer:e

Step-by-step explanation:

The equation for the submarine is given as y =-240x

Where y is the distance of the descent

x is the time in hours

and -240 is the rate of distance per unit time

To calculate how long it will take this submarine to reach the descent

x = y /-240

8 0

3 years ago

Which numeral represents a larger quantity? 10.2 base ten or 10.7 base eight

Whitepunk [10]

You would need to explain base ten and base 8

6 0

3 years ago

A contractor is required by a county planning department to submit one, two, three, four, or five forms (depending on the nature

Westkost [7]

Answer:

(a) The value of k is $\frac{1}{15}$ .

(b) The probability that at most three forms are required is 0.40.

(d) $P(y)=\frac{y^{2}}{50} ;\ y=1, 2, ...5$ is not the pmf of y.

Step-by-step explanation:

The random variable Y is defined as the number of forms required of the next applicant.

The probability mass function is defined as:

$P(y) = \left \{ {{ky};\ for \ y=1,2,...5 \atop {0};\ otherwise} \right$

(a)

The sum of all probabilities of an event is 1.

Use this law to compute the value of k.

$\sum P(y) = 1\\k+2k+3k+4k+5k=1\\15k=1\\k=\frac{1}{15}$

Thus, the value of k is $\frac{1}{15}$ .

(b)

Compute the value of P (Y ≤ 3) as follows:

$P(Y\leq 3)=P(Y=1)+P(Y=2)+P(Y=3)\\=\frac{1}{15}+\frac{2}{15}+ \frac{3}{15}\\=\frac{1+2+3}{15}\\ =\frac{6}{15} \\=0.40$

Thus, the probability that at most three forms are required is 0.40.

(c)

Compute the value of P (2 ≤ Y ≤ 4) as follows:

$P(2\leq Y\leq 4)=P(Y=2)+P(Y=3)+P(Y=4)\\=\frac{2}{15}+\frac{3}{15}+\frac{4}{15}\\ =\frac{2+3+4}{15}\\ =\frac{9}{15} \\=0.60$

Thus, the probability that between two and four forms (inclusive) are required is 0.60.

(d)

Now, for $P(y)=\frac{y^{2}}{50} ;\ y=1, 2, ...5$ to be the pmf of Y it has to satisfy the conditions:

$P(y)=\frac{y^{2}}{50}>0;\ for\ all\ values\ of\ y \\$
$\sum P(y)=1$

Check condition 1:

$y=1:\ P(y)=\frac{y^{2}}{50}=\frac{1}{50}=0.02>0\\y=2:\ P(y)=\frac{y^{2}}{50}=\frac{4}{50}=0.08>0 \\y=3:\ P(y)=\frac{y^{2}}{50}=\frac{9}{50}=0.18>0\\y=4:\ P(y)=\frac{y^{2}}{50}=\frac{16}{50}=0.32>0 \\y=5:\ P(y)=\frac{y^{2}}{50}=\frac{25}{50}=0.50>0$

Condition 1 is fulfilled.

Check condition 2:

$\sum P(y)=0.02+0.08+0.18+0.32+0.50=1.1>1$

Condition 2 is not satisfied.

Thus, $P(y)=\frac{y^{2}}{50} ;\ y=1, 2, ...5$ is not the pmf of y.

7 0

2 years ago

How to put 35.99 in a mix number

Anon25 [30]

35 99/100 (35 wholes 99 over 100)

6 0

3 years ago

Please help me with this

timofeeve [1]

6 divided by 4(3/5)
After multiplying the fraction we get 23/5
Dividing a fraction will result to multiplying
6 * 23/5
138/5 is the answer.

8 0

3 years ago