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jolli1 [7]
4 years ago
15

How to solve ratio tables with decimals

Mathematics
1 answer:
DiKsa [7]4 years ago
3 0
0.7 is 0:7 in reatio

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Along which axis is the dependent variable traditionally plotted?
Dvinal [7]
The y axis for dependent variables and x axis for independent
7 0
3 years ago
Select the correct answer from each drop-down menu.
Annette [7]

All of given options contain quadratic functions. One way to determine the extreme value is squaring the expression with variable x.

Option B contain the expression where you can see perfect square. Thus, equation \bf{y=-(x-2)^2+5} (choice B) reveals its extreme value without needing to be altered.

To determine the extreme value of this equation, you should substitute x=2 (x-value that makes expression in brackets equal to zero) into the function notation:

y=-(2-2)^2+5=5.

The extreme value of this equation has a minimum at the point (2,5).

7 0
3 years ago
Read 2 more answers
Im going to say this right now please stop giving me answers from other links or ones that have been copied your answer can be r
enot [183]

Answer:

D. Collinear

Step-by-step explanation:

Three points lying on a line are collinear because they share the same line.

the rest of the options can be ruled out because the points can not be congruent due to lack of distance information and the same goes for midpoint and equal.

3 0
3 years ago
67% of x = 67 <br> Can Yall Help Me
Aneli [31]
67% of x = 67......turn ur percent to a decimal..." of " means multiply

0.67x = 67
x = 67 / 0.67
x = 100 <==
7 0
4 years ago
The table shows a linear function. <br><br> Which equation represents the function.
mote1985 [20]

Answer:

\large\boxed{f(x)=\dfrac{3}{2}x-1}

Step-by-step explanation:

\text{The slope-intercept formula:}\\\\y=mx+b\\\\m\ -\ slope\\b\ -\ y-intercept\\\\\text{The formula of a slope:}\\\\m=\dfrac{y_2-y_1}{x_2-x_1}\\\\\text{From the table we hve two points (0, -1) and (2, 2). Substitute:}\\\\m=\dfrac{2-(-1)}{2-0}=\dfrac{3}{2}

\text{Therefore the equation is}\ f(x)=\dfrac{3}{2}x-1\\\\\text{Check for  the point (4, 5):}\\\\f(4)=\dfrac{3}{2}(4)-1=(3)(2)-1=6-1=5\qquad\ CORRECT

7 0
3 years ago
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