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3 years ago

How to solve ratio tables with decimals

Mathematics

1 answer:

DiKsa [7]3 years ago

3 0

0.7 is 0:7 in reatio

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A newly launched clothing line is rapidly increasing in popularity. Every month 20% more items of clothing are sold. If 70,800 i

prohojiy [21]

Answer:

<u>212,400 items</u> were sold in 10 months.

Step-by-step explanation:

Given:

Items sold this month = 70,800

Percent Increase in every month = 20%

We need to find number of items sold in coming 10 months.

Solution:

First we will find number of items increase in each month.

number of items increase in each month can be calculated by Percent Increase in every month multiplied by Items sold this month and the divided by 100.

number of items increase in each month = $\frac{20}{100} \times 70800 = 14,160$

Now we will find number of item sold in 10 months.

number of item sold in 10 months is equal to sum of Items sold this month and number of items increase in each month multiplied by 10.

framing in equation form we get;

number of item sold in 10 months = $70800+10\times 14160 = 212,400$

Hence <u>212,400 items</u> were sold in 10 months.

8 0

3 years ago

i am a number less than 3,000. when you divide me by 32,my remainder is 30. when you divide me by 58,my remainder is 44. what nu

Marat540 [252]

32(24)+30=58(13)+44=798

I am 798

3 0

3 years ago

Martin is making squares by arranging 26 sticks. how many squares can he make? Write and solve the number fact you used to find

Alexxx [7]

He could make 6 squares, because each square has 4 sides. And 24 divided by 4 is 6. The number fact that i used is 24 divided by 4

6 0

3 years ago

Round 6,877 to the nearest whole number.

Snowcat [4.5K]

When you round that number you get 7,000

4 0

3 years ago

Csc^3x-csc^2x-cscx+1=cot^2x(cscx-1)

belka [17]

Verify the identity:

$csc^3x-csc^2x-cscx+1\qquad =cot^2x(cscx-1)\\\\csc^2x(cscx-1)-1(cscx-1) =\quad \downarrow\\\\(csc^2x-1)(cscx-1)\quad \qquad \ =\quad \downarrow\\\\\bigg(\dfrac{1}{sin^2x}-\dfrac{sin^2x}{sin^2x}\bigg)(cscx-1)\ =\quad \downarrow\\\\\\\bigg(\dfrac{1-sin^2x}{sin^2x}\bigg)(cscx-1)\qquad \ =\quad \downarrow\\\\\\\bigg(\dfrac{cos^2x}{sin^2x}\bigg)(cscx-1)\qquad \qquad =\quad \downarrow\\\\\\cot^2x(cscx-1)\qquad \qquad \qquad =cot^2x(cscx-1)\qquad \checkmark$

5 0

2 years ago

Read 2 more answers