The future value (A) of a principal amount P compounded 12 times per year at rate r for t years is given by
A = P·(1 + r/12)^(12t)
Substitute the given values and solve for t.
3000 = 175·(1 + .03/12)^(12t)
Taking logarithms, this becomes
log(3000) = log(175) + 12t·log(1.0025)
(log(3000) -log(175))/(12·log(1.0025)) = t
t ≈ 94.84
It will take 95 years for the balance to grow by a factor of 17 to $3000.
Answer:
- D. The experimental data does not support Sally’s hypothesis.
Step-by-step explanation:
<u>Sally's hypothesis can be shown as:</u>
- 8c = 1p, where c- coil, p- paper clip
<u>From the data in the table we can see that:</u>
- 8c = 2p ⇒ 4c = 1p
- 16c = 4p ⇒ 4c = 1p
- 24c = 6p ⇒ 4c = 1p
As we see there is a difference, Sally can pick up one paper clip for each 4 coils.
Correct answer choice is D.
Answer:
60% of the people surveyed were satisfied with the car
Step-by-step explanation:
1140 satisfied people / 1900 total people = 0.60 = 60% satisfied people
Answer: The answer is B
Step-by-step explanation:
Given :-
- The general term of a sequence is given by aₙ=43-3(n-1) .
To Find :-
- The first four terms of the sequence.
Solution :-
The given expression is 
→ aₙ=43-3(n-1)
where n > 0
<u>Finding</u><u> the</u><u> </u><u>first </u><u>term </u><u>:</u>
Substituting n = 1 , we have ,
→ T1 = 43 - 3(1-1)
→ T1 = 43 - 3*0
→ T1 = 43 - 0 = 43
<u>Finding</u><u> the</u><u> </u><u>second</u><u> </u><u>term </u><u>:</u>
Substituting n = 2 , we have,
→ T2 = 43 -3(2-1)
→ T2 = 43 -3*1
→ T2 = 43 -3 = 40
<u>Finding</u><u> </u><u>the </u><u>third </u><u>term</u><u> </u><u>:</u>
Substituting n = 3 , we have,
→ T3 = 43 -3(3-1)
→ T3 = 43 -3*2
→ T3 = 43 -6 = 37
<u>Finding</u><u> the</u><u> </u><u>fourth</u><u> </u><u>term </u><u>:</u>
→ T4 = 43 -3(4-1)
→ T4 = 43 -3*3
→ T4 = 43-9 = 34
<u>Hence</u><u> the</u><u> </u><u>first</u><u> </u><u>four</u><u> terms</u><u> of</u><u> </u><u>the</u><u> </u><u>sequence</u><u> </u><u>are </u><u>4</u><u>3</u><u> </u><u>,</u><u> </u><u>4</u><u>0</u><u> </u><u>,</u><u> </u><u>37</u><u> </u><u>and </u><u>34</u><u> </u><u>.</u>
<em>I </em><em>hope</em><em> this</em><em> helps</em><em> </em><em>.</em><em> </em><em>Let </em><em>me</em><em> know</em><em> if</em><em> you</em><em> </em><em>need </em><em>further</em><em> </em><em>clarification</em><em> </em><em>.</em>