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3 years ago

Let f(x)=3x-7 and g(x)=2x². Perform the function operation and then find the domain of the result.

Mathematics

1 answer:

olya-2409 [2.1K]3 years ago

6 0

Answer: A

Step-by-step explanation:

$f(x)=3x-7\\g(x)=2x^2$

$(f-g)(x)=3x-7-(2x^2)\\(f-g)(x)=3x-7-2x^2\\(f-g)(x)=-2x^2+3x-7$

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Five bells begin to ring together and they ring at intervals of 3, 6, 10, 12 and 15 seconds, respectively. How many times will t

Evgen [1.6K]

Answer:

60 times will they ring together at the same second in one hour excluding the one at the end.

Step-by-step explanation:

Given : Five bells begin to ring together and they ring at intervals of 3, 6, 10, 12 and 15 seconds, respectively.

To find : How many times will they ring together at the same second in one hour excluding the one at the end?

Solution :

First we find the LCM of 3, 6, 10, 12 and 15.

2 | 3 6 10 12 15

2 | 3 3 5 6 15

3 | 3 3 5 3 15

5 | 1 1 5 1 5

| 1 1 1 1 1

$LCM(3, 6, 10, 12,15)=2\times 2\times 3\times 5$

$LCM(3, 6, 10, 12,15)=60$

So, the bells will ring together after every 60 seconds i.e. 1 minutes.

i.e. in 1 minute they rand together 1 time.

We know, 1 hour = 60 minutes

So, in 60 minute they rang together 60 times.

Therefore, 60 times will they ring together at the same second in one hour excluding the one at the end.

6 0

3 years ago

Order these numbers in ascending order. -11/3, 90%, 89/4, 2

Delicious77 [7]

Answer:

$- \frac{11}{3} \: \: » \: \: 90\% \: » \: \: 2 \: \: » \: \: \frac{89}{4}$

5 0

3 years ago

Angel and Jayden were at track practice. The track is 2/5 kilometers around.  Angel ran 1 lap in 2 minutes.  Jayden ran 3 laps

choli [55]

Answer:

6/25 km in 1 min; or 0.24 km/min

Step-by-step explanation:

The info about Angel is not necessary.

Jayden runs 3 laps in 5 mins

Each lap is 2/5 km, so Jayden runs 3 x (2/5 km) in 5 min = 6/5 km in 5 min.

Distance = rate x time

6/5 km = rate (5 min)

We want to isolate r (rate), so divide both sides by 5 min

6/5 km ÷ 5 min = r

6/5 km (1/5 min) = r

6/25 km/min = r (notice how the units worked out correctly to km/min)

So, Jayden runs 6/25 km in 1 min.

7 0

3 years ago

Read 2 more answers

Question:

aivan3 [116]

Answer:

part A) The scale factor of the sides (small to large) is 1/2

part B) Te ratio of the areas (small to large) is 1/4

part C) see the explanation

Step-by-step explanation:

Part A) Determine the scale factor of the sides (small to large).

we know that

The dilation is a non rigid transformation that produce similar figures

If two figures are similar, then the ratio of its corresponding sides is proportional

Let

z ----> the scale factor

$\frac{CB}{C'B'}=\frac{CD}{C'D'}=\frac{BD}{B'D'}$

The scale factor is equal to

$z=\frac{CB}{C'B'}$

substitute

$z=\frac{4}{8}$

simplify

$z=\frac{1}{2}$

Part B) What is the ratio of the areas (small to large)?

<em>Area of the small triangle</em>

$A=\frac{1}{2}(2)(4)=4\ units^2$

<em>Area of the large triangle</em>

$A=\frac{1}{2}(4)(8)=16\ units^2$

ratio of the areas (small to large)

$ratio=\frac{4}{16}=\frac{1}{4}$

Part C) Write a generalization about the ratio of the sides and the ratio of the areas of similar figures

In similar figures the ratio of its corresponding sides is proportional and this ratio is called the scale factor

In similar figures the ratio of its areas is equal to the scale factor squared

4 0

4 years ago

HELPPPPP PLEASEEEEEEEE I BEG YOU!!! SCHOOL IS ENDING SOON

Mars2501 [29]

Answer:

option c 1000

Step-by-step explanation:

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6 0

3 years ago

Read 2 more answers