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nadya68 [22]
3 years ago
14

So its 7:10am in AZ and I'm bored hbu?

Mathematics
1 answer:
Flura [38]3 years ago
5 0

Answer:   its 9:11 in alabama

im bored toooo

are u virtual or nah

Step-by-step explanation:

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How many solutions are there to this system of equations?
Inessa05 [86]

Answer:

no solution

Step-by-step explanation:

the solution to a system of equations is at the points of intersection of the 2 lines.

the equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

y = \frac{1}{4} x - 4 ← is in slope- intercept form

with slope m = \frac{1}{4}

y = \frac{1}{4} x - 1 ← is in slope- intercept form

with slope m = \frac{1}{4}

• Parallel lines have equal slopes

then the 2 lines are parallel and never intersect.

Thus the system of equations has no solution

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2 years ago
Colton has 32 blue marbles and 24 white marbles. If he wants to put them in identical groups without any left over, what is the
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The awnser is 50 because 32 divided by 47 is 50
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Please help!! x = 2 - 3 cos t, y = 1 + 4 sin t in rectangular form?<br><br> thank you! :)
sukhopar [10]

Answer:

\frac{(x-2)^2}{9}+\frac{(y-1)^2}{16}=1

Step-by-step explanation:

x=2-3\cos(t)

y=1+4\sin(t)

Let's solve for \cos(t) in the first equation and then solve for \sin(t) in the second equation.

I will then use the following identity to get right of the parameter, t:

\cos^2(t)+\sin^2(t)=1 (Pythagorean Identity).

Let's begin with x=2-3\cos(t).

Subtract 2 on both sides:

x-2=-3\cos(t)

Divide both sides by -3:

\frac{x-2}{-3}=\cos(t)

Now time for the second equation, y=1+4\sin(t).

Subtract 1 on both sides:

y-1=4\sin(t)

Divide both sides by 4:

\frac{y-1}{4}=\sin(t)

Now let's plug it into our Pythagorean Identity:

\cos^2(t)+\sin^2(t)=1

\frac{x-2}{-3})^2+(\frac{y-1}{4})^2=1

\frac{(x-2)^2}{(-3)^2}+\frac{(y-1)^2}{4^2}=1

\frac{(x-2)^2}{9}+\frac{(y-1)^2}{16}=1

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Three that are equivalent are 12:9 8:6 28:21
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Which of the following facts would be sufficient to
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